如何修复Ora-01427单行子查询在select中返回多行?

问题描述 投票:7回答:2

当我执行以下查询时,我得到的消息就像

“Ora-01427单行子查询返回多行”

SELECT E.I_EmpID AS EMPID,
       E.I_EMPCODE AS EMPCODE,
       E.I_EmpName AS EMPNAME,
       REPLACE(TO_CHAR(A.I_REQDATE, 'DD-Mon-YYYY'), ' ', '') AS FROMDATE,
       REPLACE(TO_CHAR(A.I_ENDDATE, 'DD-Mon-YYYY'), ' ', '') AS TODATE,
       TO_CHAR(NOD) AS NOD,
       DECODE(A.I_DURATION,
              'FD',
              'FullDay',
              'FN',
              'ForeNoon',
              'AN',
              'AfterNoon') AS DURATION,
       L.I_LeaveType AS LEAVETYPE,
       REPLACE(TO_CHAR((SELECT C.I_WORKDATE
                         FROM T_COMPENSATION C
                        WHERE C.I_COMPENSATEDDATE = A.I_REQDATE
                          AND C.I_EMPID = A.I_EMPID),
                       'DD-Mon-YYYY'),
               ' ',
               '') AS WORKDATE,
       A.I_REASON AS REASON,
       AP.I_REJECTREASON AS REJECTREASON
  FROM T_LEAVEAPPLY A
 INNER JOIN T_EMPLOYEE_MS E
    ON A.I_EMPID = E.I_EmpID
   AND UPPER(E.I_IsActive) = 'YES'
   AND A.I_STATUS = '1'
 INNER JOIN T_LeaveType_MS L
    ON A.I_LEAVETYPEID = L.I_LEAVETYPEID
  LEFT OUTER JOIN T_APPROVAL AP
    ON A.I_REQDATE = AP.I_REQDATE
   AND A.I_EMPID = AP.I_EMPID
   AND AP.I_APPROVALSTATUS = '1'
 WHERE E.I_EMPID <> '22'
 ORDER BY A.I_REQDATE DESC

当我执行此操作而没有ORDER BY A.I_REQDATE DESC时,它返回100行...

sql oracle
2个回答
8
投票

使用以下查询:

SELECT E.I_EmpID AS EMPID,
       E.I_EMPCODE AS EMPCODE,
       E.I_EmpName AS EMPNAME,
       REPLACE(TO_CHAR(A.I_REQDATE, 'DD-Mon-YYYY'), ' ', '') AS FROMDATE,
       REPLACE(TO_CHAR(A.I_ENDDATE, 'DD-Mon-YYYY'), ' ', '') AS TODATE,
       TO_CHAR(NOD) AS NOD,
       DECODE(A.I_DURATION,
              'FD',
              'FullDay',
              'FN',
              'ForeNoon',
              'AN',
              'AfterNoon') AS DURATION,
       L.I_LeaveType AS LEAVETYPE,
       REPLACE(TO_CHAR((SELECT max(C.I_WORKDATE)
                         FROM T_COMPENSATION C
                        WHERE C.I_COMPENSATEDDATE = A.I_REQDATE
                          AND C.I_EMPID = A.I_EMPID),
                       'DD-Mon-YYYY'),
               ' ',
               '') AS WORKDATE,
       A.I_REASON AS REASON,
       AP.I_REJECTREASON AS REJECTREASON
  FROM T_LEAVEAPPLY A
 INNER JOIN T_EMPLOYEE_MS E
    ON A.I_EMPID = E.I_EmpID
   AND UPPER(E.I_IsActive) = 'YES'
   AND A.I_STATUS = '1'
 INNER JOIN T_LeaveType_MS L
    ON A.I_LEAVETYPEID = L.I_LEAVETYPEID
  LEFT OUTER JOIN T_APPROVAL AP
    ON A.I_REQDATE = AP.I_REQDATE
   AND A.I_EMPID = AP.I_EMPID
   AND AP.I_APPROVALSTATUS = '1'
 WHERE E.I_EMPID <> '22'
 ORDER BY A.I_REQDATE DESC

诀窍是通过添加聚合函数强制内部查询只返回一条记录(我在这里使用了max())。就查询而言,这将完美地工作,但是,老实说,OP应该通过检查数据来调查内部查询返回多个记录的原因。这些多条记录真的与商业明智相关吗?


4
投票

唯一的子查询似乎是这样 - 尝试将ROWNUM限制添加到可确定的位置:

(SELECT C.I_WORKDATE
         FROM T_COMPENSATION C
         WHERE C.I_COMPENSATEDDATE = A.I_REQDATE AND ROWNUM <= 1
         AND C.I_EMPID = A.I_EMPID)

你需要调查为什么这不是唯一的,但是 - 例如该员工可能在匹配日期有多个C.I_COMPENSATEDDATE

出于性能原因,您还应该查看查找子查询是否可以重新排列为内/左连接,即

 SELECT 
    ...
    REPLACE(TO_CHAR(C.I_WORKDATE, 'DD-Mon-YYYY'),
            ' ',
            '') AS WORKDATE,
    ...
 INNER JOIN T_EMPLOYEE_MS E
    ...
     LEFT OUTER JOIN T_COMPENSATION C
          ON C.I_COMPENSATEDDATE = A.I_REQDATE
          AND C.I_EMPID = A.I_EMPID
    ...
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