Android studio Call方法

Question

我的代码有问题。我有一个EditText的活动，当活动第一次打开时，我想将EditText的值传递给我的服务器并收到答案。

问题是如果我在onCreate ()中调用该方法它不起作用。

相反，如果我从click ()的button事件调用该方法，它的工作原理。

有没有办法从onCreate ()调用方法并显示EditText的内容？

这是我的代码：

 @Override
 protected void onCreate(Bundle savedInstanceState) {
     super.onCreate(savedInstanceState);
     setContentView(R.layout.activity_main3);

     First_Name = (EditText)findViewById(R.id.editText50);

     parseContent = new ParseContentRistoratore(this);
     preferenceHelper = new PreferenceHelperRistoratore(this);

     CheckEditTextIsEmptyOrNot();

     UserRegisterFunction(F_Name_Holder);

     prova = (Button) findViewById(R.id.button10);
     // If EditText is not empty and CheckEditText = True then this block will execute.
     prova.setOnClickListener(new View.OnClickListener() {
         @Override
         public void onClick(View v) {
         }
     });
 }

 //REGISTRATION
 @RequiresApi(api = Build.VERSION_CODES.CUPCAKE)
 public void UserRegisterFunction(final String fk_id_ristorante){
     class UserRegisterFunctionClass extends AsyncTask<String,Void,String> {
         @Override
         protected void onPostExecute(String httpResponseMsg) {
             super.onPostExecute(httpResponseMsg);

            if(httpResponseMsg.equalsIgnoreCase("Prova gratuita terminata")){
                //  finish();  con finish(); l'attività finisce
                Intent intent = new Intent(Main3Activity.this, Versione_scaduta.class);
                startActivity(intent);
            }
        }

        //REGISTRATION
        @Override
        protected String doInBackground(String... params) {
            hashMap.put("fk_id_ristorante",params[0]);
            finalResult = httpParse.postRequest(hashMap, HttpURLRegister);
            return finalResult;
        }
    }

    UserRegisterFunctionClass userRegisterFunctionClass = new UserRegisterFunctionClass();
    userRegisterFunctionClass.execute(fk_id_ristorante);
}

//REGISTRAZIONE
public void CheckEditTextIsEmptyOrNot(){
    F_Name_Holder = First_Name.getText().toString();

    if(TextUtils.isEmpty(F_Name_Holder) )
    {
        CheckEditText = false;
    }
    else {
        CheckEditText = true ;
    }
}

@Override
protected void onResume() {
    super.onResume();

    AccountKit.getCurrentAccount(new AccountKitCallback<Account>() {
        @Override
        public void onSuccess(Account account) {
            //editUserId = (EditText)findViewById(R.id.editUserEmail);
            // editUserId.setText(String.format("Email Id %s",account.getEmail()));

            First_Name.setText(String.format("r%s", account.getId()));
        }

        @Override
        public void onError(AccountKitError accountKitError) {
        }
    });
}

}

如果你做不到，我想知道其他的事情。

为什么在我的PHP代码中如果我从Else中删除IF Cycle代码在Android studio上启动时不起作用？

<?php
if($_SERVER['REQUEST_METHOD']=='POST'){

include 'config.php'; 

 $con = mysqli_connect($HostName,$HostUser,$HostPass,$DatabaseName);

 $fk_id_ristorante = $_POST['fk_id_ristorante'];



 $CheckSQL = "SELECT * FROM R_Iscrizioni WHERE data_scadenza < CURDATE() AND fk_id_ristorante='$fk_id_ristorante' AND pagamento = 'No' ";

 $check = mysqli_fetch_array(mysqli_query($con,$CheckSQL));

 if(isset($check)){

 echo 'Prova gratuita terminata';
}
else {
echo 'Hello';
}
}
 mysqli_close($con);
?>

Answer 1

您需要做的就是使用CountDownTimer让系统加载并准备好让您的代码正确执行。

希望这能帮到你。