正则表达式排除特定字符串

Question

我需要一个.NET正则表达式匹配来自"[@foo]"的"applicant_data/contact_number[@foo]" w / c我已经可以使用模式"\[@(.*?)\]"。

但是我想做一个例外，以便"applicant_data/contact_number[@foo=2]"与模式不匹配。所以问题是正则表达式应该是什么，以便它将获得任何有效的字母数字（[@ bar]，[@ theVar]，[@ zoo $ 6]）但不是[@ bar = 1]，[@ theVar = 3] ？

Answer 1

你可以试试这个：

\[@[\w-]+(?!=)\]

说明：

"\[" &       ' Match the character “[” literally
"@" &        ' Match the character “@” literally
"[\w-]" &    ' Match a single character present in the list below
                ' A “word character” (Unicode; any letter or ideograph, digit, connector punctuation)
                ' The literal character “-”
   "+" &        ' Between one and unlimited times, as many times as possible, giving back as needed (greedy)
"(?!" &      ' Assert that it is impossible to match the regex below starting at this position (negative lookahead)
   "=" &        ' Match the character “=” literally
")" &
"\]"         ' Match the character “]” literally

希望这可以帮助！

Answer 2

试试这个正则表达式：

\[@(?![^\]]*?=).*?\]

Click for Demo

说明：

• \[@ - 字面上匹配[@
• (?![^\]]*?=) - 负向前瞻以确保在下一个=之前]不在任何地方
• .*? - 匹配除换行符之外的任何字符的0+次出现
• \] - 字面上匹配]