PHP PDO查询问题返回为object =>“queryString”[关闭]

Question

我正在使用PDO并将我的查询放入try块，我准备它，然后调用execute on it，接下来就是fetchAll(PDO::FETCH_ASSOC)。在行中我需要文本我将PHP放在foreach循环中，$tools变量为$obj。然后我“思考”我正在调用，因为我在代码中添加了变量$obj，引用了来自mySQL的'name'，'price'和'code'。只是吐出查询字符串object(PDOStatement)#2(1){["queryString"]}=>...the Sql statmement.的错误

try {
    $tools = $dbh->prepare("SELECT t.item_code as code, t.item_name as 
 name, t.retail_price as retail,
                            t.sale_price as price, t.item_pieces as 
 pieces, t.qty as quantity,
                             t.sold as sold, b.brand as brand, 
 c.category as category 
                                 FROM Tools AS t 
                                 JOIN Images AS i ON t.t_id = i.t_id
                                  JOIN Brands AS b ON t.b_id = b.b_id 
                                 JOIN Categories AS c ON t.c_id = 
c.c_id 
                                 LEFT OUTER JOIN Types as tt ON tt.t_id = t.tt_id");
    $tools->execute();
    $tools->fetchAll(PDO::FETCH_ASSOC);
 }catch (PDOException $e) {
    echo 'unable to retrieve data';
     echo $e->getMessage();
    exit();
}
<?php
                    foreach($tools as $obj)  {
                    ?>
                    <div class="col-xs-12 col-sm-6 col-md-3">
                         <article class="card">
                            <p class="text-center">
                                Item: <?php echo $obj->name; ?><br>
                                Brand: <br>
                                Price: <?php echo $obj->price; ?><br>
                                <button class="btn btn-default btn-lg" 
value="<?php echo $obj->name; ?>">
                                    <a href="#"><?php echo $obj->code; 
 ?></a>
                                </button>
                            </p>
                         </article>
                     </div>
                     <?php }  ?>

网页中的代码消息。

`object(PDOStatement)#2 (1) { ["queryString"]=> string(609) "SELECT t.item_code as code, t.item_name as name, t.retail_price as retail, t.sale_price as price, t.item_pieces as pieces, t.qty as quantity, t.sold as sold, b.brand as brand, c.category as category FROM Tools AS t JOIN Images AS i ON t.t_id = i.t_id JOIN Brands AS b ON t.b_id = b.b_id JOIN Categories AS c ON t.c_id = c.c_id LEFT OUTER JOIN Types as tt ON tt.t_id = t.tt_id" }`

Answer 1

$tools->fetchAll(PDO::FETCH_ASSOC);是一个问题。 fetchAll从语句中获取所有行并返回它们。如果您要使用它，则需要将该表达式的结果分配给另一个变量，例如：

$results = $tools->fetchAll(PDO::FETCH_ASSOC);

然后你可以foreach($results...而不是foreach($tools...

---

或者，您应该能够删除fetchAll表达式。 PDOStatement实现了可遍历，并且可以在执行后直接使用foreach进行迭代，而无需显式使用fetch方法。