从 Swift 到 PHP 服务器的 Post 请求以 $_POST 的键发送

Question

在 Swift 中发出基本的 post 请求，并且值在 $_POST 数组的键中接收。

快速代码：

        struct TestResponse: Codable{
           let test: String
        }
   
       func postData<T:Codable>( parameters: T, completion: @escaping (Data?, URLResponse?, Error?) -> Void) {
        
        let urlString = "http://example.com"
        
        var request = URLRequest(url: URL(string: urlString)! )
        request.addValue("XMLHttpRequest", forHTTPHeaderField: "X-Requested-With")
        request.setValue("application/json, text/javascript, /; q=0.01", forHTTPHeaderField: "Accept")
        request.httpMethod = "POST"
        request.httpBody = try! JSONEncoder().encode(parameters)
        URLSession.shared.dataTask(with: request) { data, response, error in
            completion(data, response, error)
        }.resume()
    }

    //sent variable as parameters
    let test = TestResponse(test: "string with space")

我得到的是：

[{"test":"string_with_space"}] =>

看起来像 $_POST 数组的键中的整个序列化 JSON 字符串，以及它的空值。 我对此很陌生。我确信我缺少诸如标题之类的东西。

我试图将请求作为帖子键中的变量名称和 $_POST 值中的变量值分发到 PHP post 请求中。

Answer 1

因此，我找到的解决方案是将请求正文视为字符串，并为要在发布请求中发送的每个项目设置内容配置：

func createMultipartBody(boundary:String, parameters: [String: String], images: [UIImage]) -> Data {
    let body = NSMutableData()
    
    // Add parameters
    for (key, value) in parameters {
        body.appendString("--\(boundary)\r\n")
        body.appendString("Content-Disposition: form-data; name=\"\(key)\"\r\n\r\n")
        body.appendString("\(value)\r\n")
    }
    
    body.appendString("--\(boundary)--\r\n")
    
    return body as Data
}

这是一个为我创建发布请求的函数：

func postDataRequest( parameters: [String:String], action: String, completion: @escaping (Data?, URLResponse?, Error?) -> Void) {
    let boundary = "Boundary-\(UUID().uuidString)"
    let body = createMultipartBody(boundary:boundary, parameters: parameters)

    guard let baseURL = UserDefaults.standard.string(forKey: "baseURL") else { return }
    guard let url = URL(string: "\(baseURL)/\(action)") else { return }
    var request = URLRequest(url: url)
    
    request.httpMethod = "POST"
    request.setValue("multipart/form-data; boundary=\(boundary)", forHTTPHeaderField: "Content-Type")
    request.setValue(String(body.count), forHTTPHeaderField: "Content-Length")
    request.addValue("XMLHttpRequest", forHTTPHeaderField: "X-Requested-With")
    request.httpBody = body
    
    URLSession.shared.dataTask(with: request) { data, response, error in
        completion(data, response, error)
    }.resume()
}

要发送图像，您还必须根据图像 mimetype 设置内容类型，并附加图像数据。此示例适用于 jpeg，图像是 UIImage 对象：

if let imageData = image.jpegData(compressionQuality: 0.7) {
    let filename = "\(UUID().uuidString).jpg"
    let mimetype = "image/jpeg"

    body.appendString("--\(boundary)\r\n")
    body.appendString("Content-Disposition: form-data; name=\"images[]\"; filename=\"\(filename)\"\r\n")
    body.appendString("Content-Type: \(mimetype)\r\n\r\n")
    body.append(imageData)
    body.appendString("\r\n")
}