iOS本地化：复数和NSNumberFormatter

Question

是否可以将NSNumberFormatter用于NSNumber格式化以及stringdict中的复数规则？

我需要下一个带格式的数字（以千位分隔）。如果我使用NSNumberFormatter格式化数字-我收到了NSString，并且我不再使用复数规则，因为iOS无法从NSString中了解该短语是单数还是复数名词。

“ [1锻炼”单身

“ 1,732,123锻炼”复数

NSNumberFormatter* numberFormatter = ...;
[NSString stringWithFormat:NSLocalizedString(@"%@ Workouts!", @"n Workout(s)"), [numberFormatter stringFromNumber:value]]

Answer 1

经过一些研究，我发现不用NSNumberFormatter就可以分隔成千上万个数字，只需使用localizedStringWithFormat。这也使我可以使用复数规则。

[NSString localizedStringWithFormat:NSLocalizedString(@"%@ Workouts!", @"n Workout(s)"), value]

---

Localizable.stringsdict

...
<key>%@ Workouts</key>
<dict>
    <key>NSStringLocalizedFormatKey</key>
    <string>%#@Workouts@</string>
    <key>Workouts</key>
    <dict>
        <key>NSStringFormatSpecTypeKey</key>
        <string>NSStringPluralRuleType</string>
        <key>NSStringFormatValueTypeKey</key>
        <string>@</string>
        <key>one</key>
        <string>%@ Workout!</string>
        <key>other</key>
        <string>%@ Workouts!</string>
    </dict>
</dict>
....

Answer 2

您可以将数字和带格式的字符串（2个参数）传递到NSLocalizedString基本思想是使用数字控制复数规则，但使用格式化的字符串显示。

我以Swift中的Decimal为例：

let number: Decimal = 13456
let formatter: NumberFormatter = {
    let formatter = NumberFormatter()
    formatter.numberStyle = .decimal
    formatter.groupingSeparator = ","
    return formatter
}()

let formattedNumberString = formatter.string(from: number as NSDecimalNumber) ?? "-" // "13,456"

let format = NSLocalizedString(
    "workouts",
    comment: "arg1 is for number, arg2 is for formatted string"
)

let resultString = String.localizedStringWithFormat(
    format, 
    number as NSDecimalNumber, 
    formattedNumberString
)

在Localizable.stringsdict中，您可以这样做：

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>
  <key>workouts</key>
    <dict>
      <key>NSStringLocalizedFormatKey</key>
      <string>%1$#@number@</string>
      <key>number</key>
      <dict>
        <key>NSStringFormatSpecTypeKey</key>
        <string>NSStringPluralRuleType</string>
        <key>NSStringFormatValueTypeKey</key>
        <string>@</string>
        <key>one</key>
        <string>%2$@ Workout!</string>
        <key>other</key>
        <string>%2$@ Workouts!</string>
      </dict>
    </dict>
  </dict>
</plist>

在此示例中，resultString为13,456 Workouts!。如果更改number = 1，则resultString将为1 Workout!