codeigniter模型功能和查询不起作用

Question

IAM尝试在Codeigniter模型中运行查询。它可以正常工作，但是当我回荡模型函数时，查询如下。

SELECT * FROM `table1` WHERE `id` = '17'
SELECT * FROM `table1` WHERE `id` = '20'
SELECT * FROM `table1` WHERE `id` = '21'
SELECT * FROM `table1` WHERE `id` = '22'
SELECT * FROM `table1` WHERE `id` = '23' 

我的模型功能在下面给出

function get_quick_navi_menu($q_code)
{
$this->db->select("*");
$this->db->where('q_id',$q_code);
$this->db->from("table0");
$q = $this->db->get();
//echo $this->db->last_query();
$final = array();
if ($q->num_rows() > 0) 
{
foreach ($q->result() as $row) {
$this->db->select("*");
$this->db->from("table1");
$this->db->where("id",$row->id);
$q = $this->db->get();
echo $this->db->last_query();
if ($q->num_rows() > 0) {
$row->children = $q->result();
}
array_push($final, $row);
}
}

我想像下面的查询一样运行查询

SELECT * FROM `table1` WHERE `id` = '17,18,19..'

表结构

Table0

id   q_id  value1

1      2       4

2      2       5

3      2       6

Table1

t1_id   id  value1   value2

 1      1      2         2
 
 2      2      5         6
 
 3      3      8         12

查看

<ul class="dropdown-menu" aria-labelledby="dropdownMenu1" style="margin-left: 1px; opacity: .9;">
						
						<?php foreach ($menus as $menu) { ?>	
                         <li class="dropdown-submenu"><a href="#" class="pan-btn" data-look="<?php echo $menu->sceneid;?>"><?php echo $menu->title;?></a>  
                           <ul class="dropdown-menu">        <?php
            if (isset($menu->children)) {
                foreach ($menu->children as $child) {?>
                
                <li><a href="#" class="pan-btn" data-look="<?php echo $child->menu_scene;?>"><?php echo $child->menu_item;?></a></li> <?php
                }
            }
            ?></ul></li><?php } ?>
 						</ul>

控制器

$menus = $this->Home_model->get_quick_navi_menu($q_code);
$data = array('menus' => $menus);

取消输出

根据table0的ID选择值1和value2。 如何解决这个问题，请帮助。

在控制器中使用此功能

public function getTableData()
    {
        $this->db->select('GROUP_CONCAT(id) as id');
        $tbl0 = $this->db->get('table0')->row_array();
        if($tbl0) {
                $ids = explode(',', $tbl0['id']);
                $this->db->where_in('id', $ids);
                $tbl1 = $this->db->get('table1')->result_array();
                echo "<pre>"; print_r($tbl1);

        }
    }

Answer 1

希望这会帮助您;

在此处以数组名称ID中的数组名称中获取所有内容，然后在循环外使用

Answer 2

where_in 在您的控制器类中：

确保您已将模型和数据库加载到控制器或autoLoad.php

中

public function get_quick_navi_menu($q_code)
{
    $this->db->select("*");
    $this->db->where('q_id',$q_code);
    $this->db->from("table0");
    $q = $this->db->get();
    $final = array();
    if ($q->num_rows() > 0) 
    {
        foreach ($q->result() as $key => $row) 
        {
            $ids[$key] = $row->id;
            $data[$key] = $row;
        }

        $this->db->select("*");
        $this->db->from("table1");
        $this->db->where_in("id",$ids);
        $q = $this->db->get();
        //echo $this->db->last_query();
        if ($q->num_rows() > 0) 
        {
            if ( ! empty($data))
            {
                foreach ($data as $key => $item) 
                {
                    $item->children = $q->result();
                    $final[] = $item;
                }
            }

        }
    }
    return $final;
    /*print_r($final);*/
}

在您的观点中：

 $q_code = 'q_code_value';
 $data['menus'] =$this->Home_model->get_quick_navi_menu($q_code);
 /* pass the $data in the view like this*/
 $this->load->view('your_view_file_path',$data);

更多：Https：//www.codeigniter.com/user_guide/database/query_builder.html#looking-for-for-pecific-data

I建议在数据库总数上仅执行一个查询，然后使用PHP来构建多维数组。 使用

<div><?php print_r($records);?></div>

将ID数组传递给您的Where子句。  使用左连接将确保您的数组中即使是“无儿童”场景。  定期的联接（内部联接）将排除第二个没有孩子的场景。

where_in()

您的控制器应将有效载荷从模型传递到视图。

public function sceneGrouper(array $qCodes): array
{
    $result = $this->db
        ->select("t0.id AS sceneid, t0.value1 AS title, t1.id AS child_id, t1.value1 AS menu_scene, t1.value2 AS menu_item")
        ->from("table0 t0")
        ->join("table1 t1", "t1.id = t0.id", "left")
        ->where_in("t0.q_id", $qCodes)
        ->get()
        ->result();

    $grouped = [];
    foreach ($result as $row) {
        $sceneId = $row->sceneId;
        $grouped[$sceneId] ??= (object) [
            'sceneId' => $sceneId,
            'title' => $row->title,
            'children' => []
        ];

        if ($row->child_id) {  // don't bother adding empty children
            $grouped[$sceneId]->children[] = (object) [
                'id' => $row->child_id,
                'menuScene' => $row->menu_scene,
                'menuItem' => $row->menu_item
            ];
        }
    }
    return array_values($grouped);
}

在您的视图中，循环浏览分组数据。将所有内联样式移动到外部样式表，以使您的视图更可读性更易于管理。

Answer 3