减少 Spyder 绘图内存使用量

Question

我想连续多次绘制一个数组，因为它在 Spyder 上发生变化。

每次我这样做都是在一个新的情节中。经过多次迭代后，系统停止了，我猜是因为内存不足。

如何“重用”该图或将其从内存中删除，这样我就不会耗尽内存？

I want to plot an array many times in a row as it changes.

Every time I do this it is in a new plot (on Spyder). After many iterations the system stops, I presume because it is out of memory.

How do I "reuse" the plot or remove it from memory so I don't run out of memory?

```python
import numpy as np
import matplotlib.pyplot as plt
import random as rn

arr= np.zeros(100)
plt.axis([1,100,1,100])

for iterations in range (10): #in my program a much bigger number
    for n in range (100): #make a new version of the array
        arr[n] = rn.randrange(0,99)
        plt.plot(arr) #plot the new version
        plt.pause(.0001)

Answer 1

我认为您正在寻找

plt.clf

。在每次迭代的顶部放置一个将清除当前绘图，这样您就不会一遍又一遍地重新绘制同一个绘图。这还需要您重置数组 - 否则，您最终会同时绘制两个图，这并不理想。

import numpy as np
import matplotlib.pyplot as plt
import random as rn

arr= np.zeros(100)
plt.axis([1,100,1,100]) 

for iterations in range (10):
    arr = np.zeros(100)
    plt.clf()
    for n in range (100):
        arr[n] = rn.randrange(0,99)
        plt.plot(arr)
        plt.pause(.0001)

通过清除内部循环，您还会获得不同的感觉。这将使 pyplot 重写单个项目，而不是一次性清除整个数组。

import numpy as np
import matplotlib.pyplot as plt
import random as rn

arr= np.zeros(100)
plt.axis([1,100,1,100]) 

for iterations in range (10):
    for n in range (100):
        arr[n] = rn.randrange(0,99)
        plt.clf()
        plt.plot(arr)
        plt.pause(.0001)