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我希望输出的结果是这样的。tag_for_child_directed_treatment=0，如果我输入 tag_for_child_directed_treatment 否则，如果打印完整的字符串就可以了。tag_for_child_directed_treatment=0
我已经尝试用代码。
@echo off
set /P search_string= Enter the string you would like to search for:
find "%search_string%" C:\Users\Bhargav\logcat1.txt
pause
它的输出是完整的一行，有人能帮我吗？
获取字符串。从开始到(包括)搜索字符串，提取数字。
@echo off
setlocal enabledelayedexpansion
set "search_string=tag_for_child_directed_treatment"
for /f "delims=" %%a in (test.txt) do set "string=%%a"
set "string=!string:*%search_string%=!"
for /f "delims==&" %%a in ("!string!") do set "result=%%a"
echo %search_string%=%result%
批量处理这样一个字符串是很可怕的。一个更可靠的解决方案是可以用 dbenham的效用 jrepl.bat它是一个混合型的JScriptbatch脚本，完全支持REGEX，这使得这个任务变得非常简单。
@echo off
set "search_string=tag_for_child_directed_treatment"
for /f "delims=" %%a in ('type test.txt ^| jrepl ".*tag_for_child_directed_treatment=([0-9]*).*" "$1" /XSEQ') do set "result=%%a"
echo %search_string%=%result%