我想使用我的 Gtk 应用程序显示通知,但是当我运行下面的代码时,一切正常,但通知不显示,即使我单击按钮也是如此。我尝试使用桌面文件(如此答案中建议的文件)运行它,但它仍然不起作用。这是我的代码:
import gi
import sys
gi.require_version("Gtk", "3.0")
from gi.repository import Gio, Gtk
class App(Gtk.Application):
def __init__(self, *args, **kwargs):
Gtk.Application.__init__(self, *args, application_id="org.example.myapp", **kwargs)
self.window = None
def do_startup(self):
Gtk.Application.do_startup(self)
def do_activate(self):
if not self.window:
self.button = Gtk.Button(label="send notification")
self.button.connect("clicked", self.notnotnot)
self.window = Gtk.ApplicationWindow(application=self)
self.window.add(self.button)
self.window.show_all()
self.window.present()
def notnotnot(self, *args):
notification = Gio.Notification()
notification.set_body("Hello!")
self.send_notification(None, notification)
if __name__ == "__main__":
app = App()
app.run(sys.argv)
这是桌面文件org.example.myapp.desktop:
[Desktop Entry]
Type=Application
Name=My Application
Exec=python3 /home/user/programs/python/testing/SO/problem_why_is_gtk....py
Terminal=true
X-GNOME-UsesNotifications=true
我知道你不再需要答案,但是,第16行的条件将始终返回
True
,因为None
不是假的,条件应该是if self.window is not None
我发现只要将优先级设置为高就会出现通知。请注意,
Gio.Notification.set_urgent()
已弃用。您需要使用Gio.Notification.set_priority()
。这是带有相应标记的添加行的代码:
import gi
import sys
gi.require_version("Gtk", "3.0")
from gi.repository import Gio, Gtk
class App(Gtk.Application):
def __init__(self, *args, **kwargs):
Gtk.Application.__init__(self, *args, application_id="org.example.myapp", **kwargs)
self.window = None
def do_startup(self):
Gtk.Application.do_startup(self)
def do_activate(self):
if not self.window:
self.button = Gtk.Button(label="send notification")
self.button.connect("clicked", self.notnotnot)
self.window = Gtk.ApplicationWindow(application=self)
self.window.add(self.button)
self.window.show_all()
self.window.present()
def notnotnot(self, *args):
notification = Gio.Notification()
notification.set_body("Hello!")
notification.set_priority(Gio.NotificationPriority.HIGH) ### ADDED LINE
self.send_notification(None, notification)
if __name__ == "__main__":
app = App()
app.run(sys.argv)
如果您在发送通知时指定字符串 ID 而不是
None
(self.send_notification("my_notif_id", notification)
),则稍后可以使用 self.withdraw_notification("my_notif_id")
撤回通知。