用于在char数组（流）c ++中查找和替换字符串的函数

Question

我正在尝试寻找一种方法来搜索char数组中的字符串，然后在每次出现时都将其替换为另一个字符串。我对要做什么有一个很清楚的想法，但是流背后的整个语法有时会使我感到困惑。无论如何，到目前为止我的代码（不是很多）是：

string FindWord = "the";
string ReplaceWord = "can";

int i = 0;
int SizeWord = FindWord.length();
int SizeReplace = ReplaceWord.length();

while (   Memory[i] != '\0')
{
         //now i know I can probably use a for loop and 
         //then if and else statements but im just not quite sure
    i++; //and then increment my position
}

通常不是这么慢：/有什么想法吗？

Answer 1

我希望将其转换为std::string后再处理字符数组>

以下很容易遵循：-

#include<iostream>
#include<string>

int main ()
{

char memory[ ] = "This is the char array"; 
 //{'O','r',' ','m','a','y',' ','b','e',' ','t','h','i','s','\0'};

std::string s(memory);

std::string FindWord = "the";
std::string ReplaceWord = "can";


std::size_t index;
    while ((index = s.find(FindWord)) != std::string::npos)
        s.replace(index, FindWord.length(), ReplaceWord);

std::cout<<s;
return 0;
}

Answer 2

您需要two