ValueError：没有足够的值来解包（预期为 4，得到 3），gps 时间为 UTC

Question

尝试将 GPS 时间转换为 UTC 日期和时间。输入是空格分隔的 x y 秒流，输出是 x y z 日期时间流

其设计用于处理激光雷达数据，输入可能来自“las2txt -parse xyt ...”等命令。

import datetime
import fileinput

#number of seconds between the start of unix time (Jan 1, 1970) and gps time (Jan 6, 1980)
offset = 315964800


def countleaps(gpsTime):
  """Count number of leap seconds that have passed."""

  # a tuple of the gps times where leap seconds were added
  leaps = (
    46828800, 78364801, 109900802, 173059203, 252028804,
    315187205, 346723206, 393984007, 425520008, 457056009,
    504489610, 551750411, 599184012, 820108813, 914803214, 
    1025136015
    )

  nleaps = 0
  for leap in leaps:  
    if gpsTime >= leap:
       nleaps += 1
  
  return nleaps

if __name__ == '__main__':
  for line in fileinput.input(E:\LiDAR\Staging\GW_Workspace\Beaverhead_Reports\BH_0001.txt):
    xvalue, yvalue, zvalue, timevalue=line.split(' ')[:4]
    gpstime=float(timevalue)
    gpstime += 1e9; # unadjusted GPS time
    unixtime = gpstime + offset - countleaps(gpstime);
    datetimestr = datetime.datetime.fromtimestamp(unixtime).strftime('%Y-%m-%d %H:%M:%S')
    
    print xvalue, yvalue, zvalue, datetimestr

错误：

Traceback (most recent call last):
  File "C:\Users\cwc051\PycharmProjects\sandbox\.venv\Sanbox_script.py", line 29, in <module>
    xvalue, yvalue, zvalue, timevalue=line.split(' ') [:4]
    ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
ValueError: not enough values to unpack (expected 4, got 3)

Answer 1

您的问题在这里：

timevalue=line.split(' ')[:4]

您告诉 python“使用分割操作产生的数组中的前四个元素为这四个变量赋值”，但根据您收到的错误内容，至少一个

line

只有两个其中有空格，因此数组只有三个元素，因此没有第四个元素可分配给

timevalue

变量。