列表的长度过滤器无法正常工作

Question

我正在制作一个二进制随机化程序，该程序将文本随机化，然后输出随机二进制。但在将 7 位二进制对象返回到列表的部分无法正常工作。

import random
message = input('What is your message? ')
def encrypter(message):
    shuffled = []
    second = []
    ascii,binary = [],[]
    for letter in message:
        ascii.append(ord(letter))
    for letter in ascii:
        binary.append(int(bin(letter)[2:]))
    print(binary)
    for character in binary:
        for digit in str(character):
            shuffled.append(digit)
    print(shuffled)
    random.shuffle(shuffled)
    print(shuffled)
    previous_number = 0
    current_string = ''
    for digit in shuffled:
        if len(current_string) < 7:
            current_string += digit
            previous_number = previous_number + 1 
        elif len(current_string) == 7:
            second.append(int(current_string))
            previous_number = 0
            current_string = ''

我尝试将 elif 语句更改为 else 语句，但仍然没有成功。 它似乎无法读取字符串的长度。我还尝试将其从检查字符串的长度更改为使用类似的计数器

number = previous_number+1
if number < 7:
    etc

Answer 1

据我所知，您希望从输入的随机二进制表示中获得 7 位数字的分块输出。这将做到这一点。长度检查没有失败，但是您每次都使用

current_string = ''

重置输出，因此，即使您修复它以返回输出，您也只是继续丢弃之前的字符串。

基本上，我刚刚从规范中获取了分块代码，然后添加了一个列表理解来将分块列表中的数字连接起来。

import random

message = input('What is your message? ')

def encrypter(message, chunk_size=7):
    shuffled = []
    second = []
    ascii,binary = [],[]
    for letter in message:
        ascii.append(ord(letter))
    for letter in ascii:
        binary.append(int(bin(letter)[2:]))
    print(binary)
    for character in binary:
        for digit in str(character):
            shuffled.append(digit)
    print(shuffled)
    random.shuffle(shuffled)
    print(shuffled)
    
    chunked = [
        shuffled[i:i + chunk_size] for i in range(0, len(shuffled), chunk_size)
    ]
    joined = [''.join(item) for item in chunked]
    
    return joined
    
            
result = encrypter(message=message)
print(result)