允许您在房间之间移动的文本角色扮演游戏忽略所有测试位置的 if 语句

Question

这是一个一直困扰我的问题。这些年来我多次重新制作了这个程序，但结果都是一样的；程序会忽略所有 if 语句。就好像它知道我正在尝试编写的程序并拒绝执行。

使用打印命令，位置设置准确。没有理由忽略它。这是我制作这个程序的最新尝试：

topLeft='topLeft'
top='top'
topRight='topRight'
midLeft='midLeft'
mid='mid'
midRight='midRight'
botLeft='botLeft'
bot='bot'
botRight='botRight'

location=mid

def printError():
    print("You can't go that way!")

def topLeft():
    userInput=input('You can go south or east.')
    if userInput=='s':
        location=midLeft
    elif userInput=='e':
        location=top
    else:
        printError()
        

def top():
    userInput=input('You can go south, east, or west.')
    if userInput=='s':
        location=mid
    elif userInput=='e':
        location=topRight
    elif userInput=='w':
        location=topLeft
    else:
        printError()

def topRight():
    userInput=input('You can go south or west.')
    if userInput=='s':
        location=midRight
    elif userInput=='w':
        location=top
    else:
        printError()

def midLeft():
    userInput=input('You can go north, south or east.')
    if userInput=='n':
        location=topLeft
    elif userInput=='s':
        location=botLeft
    elif userInput=='e':
        location=mid
    else:
        printError()

def mid():
    userInput=input('You can go north, south, east, and west.')
    if userInput=='n':
        location=top
    elif userInput=='s':
        location=bot
    elif userInput=='e':
        location=midRight
    elif userInput=='w':
        location=midLeft
    else:
        printError()

def midRight():
    userInput=input('You can go north, south, west.')
    if userInput=='n':
        location=topRight
    elif userInput=='s':
        location=botRight
    elif userInput=='w':
        location=mid
    else:
        printError()

def botLeft():
    userInput=input('You can go north or east.')
    if userInput=='n':
        location=midLeft
    elif userInput=='e':
        location=bot
    else:
        printError()

def bot():
    userInput=input('You can go north, east, or west.')
    if userInput=='n':
        location=mid
    elif userInput=='e':
        location=botLeft
    elif userInput=='w':
        location=botRight
    else:
        printError()

def botRight():
    userInput=input('You can go north or west.')
    if userInput=='n':
        location=midRight
    elif userInput=='w':
        location=bot
    else:
        printError()

while True:
    print(location)
    if location==topLeft:
        topLeft()
    elif location==top:
        top()
    elif location==topRight:
        topRight()
    elif location==midLeft:
        midLeft()
    elif location==mid:
        mid()
    elif location==midRight:
        midRight()
    elif location==botLeft:
        botLeft()
    elif location==bot:
        bot()
    elif location==botRight:
        botRight()

希望代码是不言自明的。为什么这样的程序总是拒绝工作？没有其他这样的循环会忽略 if 语句。它在其他情况下也会这样做，但这是唯一具有模式的情况。我尝试制作一个基于文本的角色扮演游戏，但无论我做什么，它都会立即失败。为什么要这样做？ while 循环不喜欢大量的 if 语句吗？即使选项只有两个，它甚至也会这样做。我是否触发了某种故障保护？这是怎么回事？

Answer 1

您将每个位置（顶部、中间等）定义为字符串和函数。函数定义稍后出现，因此优先。这意味着

while

循环中的每个条件都将失败，因为它们都试图将字符串与函数进行比较。

您必须重命名函数或字符串。我个人会选择这些函数，因为您可以查找并替换“top()”而不会弄乱太多，但这取决于您。