如何为此脚本添加功能

Question

我在网上找到了这个脚本，我想添加一个提交按钮，向您发送选定的城市。抱歉这个愚蠢的问题，我是新手。

例如：

下拉选择：比利时 - >西弗兰德里 - >布鲁日

该页面将您重定向到：

https://www.yoursitename.com/city/belgium/west-flanderi/brugge

这是演示的link

的index.php

<script type="text/javascript">
  $(document).ready(function(){
$('#country').on('change',function(){
    var countryID = $(this).val();
    if(countryID){
        $.ajax({
            type:'POST',
            url:'ajaxData.php',
            data:'country_id='+countryID,
            success:function(html){
                $('#state').html(html);
                $('#city').html('<option value="">Select state first</option>'); 
            }
        }); 
    }else{
        $('#state').html('<option value="">Select country first</option>');
        $('#city').html('<option value="">Select state first</option>'); 
    }
});

$('#state').on('change',function(){
    var stateID = $(this).val();
    if(stateID){
        $.ajax({
            type:'POST',
            url:'ajaxData.php',
            data:'state_id='+stateID,
            success:function(html){
                $('#city').html(html);
            }
        }); 
    }else{
        $('#city').html('<option value="">Select state first</option>'); 
    }
});
  });
  </script>


<?php
//Include database configuration file
include('dbConfig.php');

//Get all country data
$query = $db->query("SELECT * FROM countries WHERE status = 1 ORDER BY country_name ASC");

//Count total number of rows
$rowCount = $query->num_rows;
?>
<select name="country" id="country" >
    <option value="">Select Country</option>
    <?php
    if($rowCount > 0){
        while($row = $query->fetch_assoc()){ 
            echo '<option value="'.$row['country_id'].'">'.$row['country_name'].'</option>';
        }
    }else{
        echo '<option value="">Country not available</option>';
    }
    ?>
</select>

<select name="state" id="state">
    <option value="">Select country first</option>
</select>

<select name="city" id="city">
    <option value="">Select state first</option>
</select>

ajaxData.php

    <?php
    //Include database configuration file
    include('dbConfig.php');

if(isset($_POST["country_id"]) && !empty($_POST["country_id"])){
//Get all state data
$query = $db->query("SELECT * FROM states WHERE country_id =         ".$_POST['country_id']." AND status = 1 ORDER BY state_name ASC");

//Count total number of rows
$rowCount = $query->num_rows;

//Display states list
if($rowCount > 0){
    echo '<option value="">Select state</option>';
    while($row = $query->fetch_assoc()){ 
        echo '<option     value="'.$row['state_id'].'">'.$row['state_name'].'</option>';
    }
}else{
    echo '<option value="">State not available</option>';
    }
}

if(isset($_POST["state_id"]) && !empty($_POST["state_id"])){
//Get all city data
$query = $db->query("SELECT * FROM cities WHERE state_id =     ".$_POST['state_id']." AND status = 1 ORDER BY city_name ASC");

//Count total number of rows
$rowCount = $query->num_rows;

//Display cities list
if($rowCount > 0){
    echo '<option value="">Select city</option>';
    while($row = $query->fetch_assoc()){ 
        echo '<option     value="'.$row['city_id'].'">'.$row['city_name'].'</option>';
    }
}else{
    echo '<option value="">City not available</option>';
}
}
?>

dbConfig.php

    <?php
    //db details
    $dbHost = 'localhost';
    $dbUsername = 'root';
    $dbPassword = '';
    $dbName = 'lisenme';

    //Connect and select the database
    $db = new mysqli($dbHost, $dbUsername, $dbPassword, $dbName);

    if ($db->connect_error) {
    die("Connection failed: " . $db->connect_error);
    }
    ?>

Answer 1

这是你如何做到的：

你基本上要做的是添加另一个必然会改变'city'选择框的事件：

$(document).ready(function(){
  $('#city').on('change',function()
  {
      var cityId = $(this).val();

      window.location.href = $('#country').val() + "/" + $('#state').val() + "/" + $(this).val();
  });
});

这是完整的例子：https://jsfiddle.net/4sy9nfg7/1/