Mulesoft 中左连接可以添加多个条件吗

Question

阵列1：

[
        { 
            "name": "Abc", 
            "address":"Mumbai",
            "phone":"91-1234567891",
            "id":123
        }, 
        { 
            "name": "Pqr", 
            "address":"Pune",
            "phone":"91-1234985438",
            "id":456
        }, 
        { 
            "name": "Abc",
            "address":"Delhi",
            "phone":"91-1234567891",
            "id":123
        }
    ]

数组2：

[
    { 
        "sid":123,
        "postalCode": "67890",
        "country": "USA",
        "sname": "tyu"
    }, 
    { 
        "sid":864,
        "postalCode": "54983",
        "country": "UK",
        "sname": "Pqr"
    }, 
    { 
        "sid":123,
        "postalCode": "27932",
        "country": "EU",
        "sname": "Uvg"
    }
]

上面我们必须考虑 ID 和名称，如果其中任何一个字段与 leftjoin 匹配，那么我们就必须考虑它们。

预期输出：

[
  {
    "name": "Abc",
    "address": "Mumbai",
    "phone": "91-1234567891",
    "id": 123,
    "sid": 123,
    "sname": "tyu",
    "postalCode": "27932",
    "country": "EU"
  },
  {
    "name": "Pqr",
    "address": "Pune",
    "phone": "91-1234985438",
    "id": 456,
    "sid": 864,
    "sname": "Pqr",
    "postalCode": "54983",
    "country": "UK"
  },
  {
    "name": "Abc",
    "address": "Delhi",
    "phone": "91-1234567891",
    "id": 123,
    "sid": 123,
    "sname": "Uvg",
    "postalCode": "27932",
    "country": "EU"
  }
]

数据编织：

%dw 2.0
output application/json
import * from dw::core::Arrays
var Array2reversed=Array2[-1 to 0] distinctBy ((item, index) -> item.sid)
var combine=leftJoin(Array1, Array2reversed, (Array1) -> Array1.name, (Array2) -> Array2.sname) map $
---
(leftJoin(combine, Array2reversed, (Array1) -> Array1.id, (Array2) -> Array2.sid)) 
    map {
        "name": $.l.name, 
        "address": $.l.address,
        "phone": $.l.phone,
        "id": $.l.id,
        "sid": $.r.sid,
        "postalCode": $.r.postalCode,
        "country": $.r.country
    }.

我们必须将 name 和 sname 视为左连接中的另一个条件。我试图放弃函数，但出现错误，并且无法仅在一个连接中加入多个条件。

Answer 1

你可以试试这个。

%dw 2.0
var Array1 = [
        { 
            "name": "Abc", 
            "address":"Mumbai",
            "phone":"91-1234567891",
            "id":123
        }, 
        { 
            "name": "Pqr", 
            "address":"Pune",
            "phone":"91-1234985438",
            "id":456
        }, 
        { 
            "name": "Abc",
            "address":"Delhi",
            "phone":"91-1234567891",
            "id":123
        }
    ]
var Array2 = [
    { 
        "sid":123,
        "postalCode": "67890",
        "country": "USA",
        "sname": "tyu"
    }, 
    { 
        "sid":864,
        "postalCode": "54983",
        "country": "UK",
        "sname": "Pqr"
    }, 
    { 
        "sid":123,
        "postalCode": "27932",
        "country": "EU",
        "sname": "Uvg"
    }
]
output application/json
import * from dw::core::Arrays
var Array2reversed=Array2[-1 to 0] distinctBy ((item, index) -> item.sid)
var combine = leftJoin(Array1, Array2reversed, (Array1) -> Array1.name, (Array2) -> Array2.sname) map ((item, index) -> item.l ++ (item.r default {}))

---
(leftJoin(combine, Array2reversed, (Array1) -> Array1.id, (Array2) -> Array2.sid)) 
    map {
        "name": $.l.name, 
        "address": $.l.address,
        "phone": $.l.phone,
        "id": $.l.id,
        "sid": $.r.sid  default $.l.sid,
        "sname": $.r.sname  default $.l.sname,
        "postalCode": $.r.postalCode default $.l.postalCode,
        "country": $.r.country default $.l.country
    }

输出

[
  {
    "name": "Abc",
    "address": "Mumbai",
    "phone": "91-1234567891",
    "id": 123,
    "sid": 123,
    "sname": "Uvg",
    "postalCode": "27932",
    "country": "EU"
  },
  {
    "name": "Pqr",
    "address": "Pune",
    "phone": "91-1234985438",
    "id": 456,
    "sid": 864,
    "sname": "Pqr",
    "postalCode": "54983",
    "country": "UK"
  },
  {
    "name": "Abc",
    "address": "Delhi",
    "phone": "91-1234567891",
    "id": 123,
    "sid": 123,
    "sname": "Uvg",
    "postalCode": "27932",
    "country": "EU"
  }
]