Firebase 将匿名用户帐户转换为永久帐户错误

Question

使用 Firebase for web 我可以成功创建匿名用户。我还可以创建一个新的电子邮件/密码用户。但是当尝试将匿名用户转换为电子邮件/密码用户时，我收到错误：

auth/provider-already-linked
User can only be linked to one identity for the given provider.

Firebase 在“将匿名帐户转换为永久帐户”部分中记录了该过程： https://firebase.google.com/docs/auth/web/anonymous-auth

这是帐户链接代码。匿名用户已登录。

return firebase.auth().createUserWithEmailAndPassword(email, password).then(newUser => {

    // Credential is being successfully retrieved. Note "any" workaround until typescript updated.
    let credential = (<any>firebase.auth.EmailAuthProvider).credential(email, password);

    firebase.auth().currentUser.link(credential)
        .then(user => { return user; })
        .catch(err => console.log(err)); // Returns auth/provider-already-linked error.
});

Answer 1

您不应致电

createUserWithEmailAndPassword

来升级匿名用户。这将注册一个新用户，注销当前登录的匿名用户。

您只需要用户的电子邮件和密码。相反，IDP 提供商（例如 Google、Facebook）将要求完成完整的登录流程，以获得令牌来识别用户。不过，我们建议对这些使用

linkWithPopup

。

示例：

// (Anonymous user is signed in at that point.)

// 1. Create the email and password credential, to upgrade the
// anonymous user.
var credential = firebase.auth.EmailAuthProvider.credential(email, password);

// 2. Links the credential to the currently signed in user
// (the anonymous user).
firebase.auth().currentUser.linkWithCredential(credential).then(function(user) {
  console.log("Anonymous account successfully upgraded", user);
}, function(error) {
  console.log("Error upgrading anonymous account", error);
});

让我知道这是否有效！

Answer 2

以匿名用户身份登录后，运行此代码以引发弹出窗口并将您的匿名用户与某些 OAUTH 提供程序连接起来

const provider = new firebase.auth.FacebookAuthProvider()
firebase.auth().currentUser.linkWithPopup(provider)
console.log(provider)

Answer 3

对于 iOS、Swift 5 创建

credential

使用

EmailAuthProvider.credential(withEmail: , password: )

示例：

let credential = EmailAuthProvider.credential(withEmail: emailTextField.text!, password: passwordTextField.text!)
        
Auth.auth().currentUser?.link(with: credential, completion: { (authDataResult: AuthDataResult?, error) in

    // ...
})