我正在使用Flasgger将Swagger UI添加到我的Python Flask应用程序中。 Internet上最常见的例子是使用@app.route
的基本Flask风格:
from flasgger.utils import swag_from
@app.route('/api/<string:username>')
@swag_from('path/to/external_file.yml')
def get(username):
return jsonify({'username': username})
这样可行。
然而,在我的应用程序中,我没有使用@app.route
装饰器来定义端点。我正在使用烧瓶蓝图。如下:
from flask import Flask, Blueprint
from flask_restful import Api, Resource
from flasgger.utils import swag_from
...
class TestResourceClass(Resource):
@swag_from('docs_test_get.yml', endpoint='test')
def get() :
print "This is the get method for GET /1.0/myapi/test endpoint"
app = Flask(__name__)
my_api_blueprint = Blueprint('my_api', __name__)
my_api = Api(my_api_blueprint)
app.register_blueprint(my_api_blueprint, url_prefix='/1.0/myapi/')
my_api.add_resource(TestResourceClass, '/test/'
endpoint='test',
methods=['GET', 'POST', 'PUT', 'PATCH', 'DELETE'])
....
如上所示,我在@swag_from
方法上使用了TestResourceClass.get()
装饰器,该方法绑定到GET方法端点。我也在两个地方匹配endpoint = test
。
但是我在Swagger UI上没有得到任何东西,它都是空白的。 docs_test_get.yml
文件确实包含有效的yaml标记来定义swagger规范。
我错过了什么?如何让Flasgger Swagger UI与基于Flask Blueprint的设置一起使用?
现在有一个https://github.com/rochacbruno/flasgger/blob/master/examples/example_blueprint.py蓝图应用程序的例子
"""
A test to ensure routes from Blueprints are swagged as expected.
"""
from flask import Blueprint, Flask, jsonify
from flasgger import Swagger
from flasgger.utils import swag_from
app = Flask(__name__)
example_blueprint = Blueprint("example_blueprint", __name__)
@example_blueprint.route('/usernames/<username>', methods=['GET', 'POST'])
@swag_from('username_specs.yml', methods=['GET'])
@swag_from('username_specs.yml', methods=['POST'])
def usernames(username):
return jsonify({'username': username})
@example_blueprint.route('/usernames2/<username>', methods=['GET', 'POST'])
def usernames2(username):
"""
This is the summary defined in yaml file
First line is the summary
All following lines until the hyphens is added to description
the format of the first lines until 3 hyphens will be not yaml compliant
but everything below the 3 hyphens should be.
---
tags:
- users
parameters:
- in: path
name: username
type: string
required: true
responses:
200:
description: A single user item
schema:
id: rec_username
properties:
username:
type: string
description: The name of the user
default: 'steve-harris'
"""
return jsonify({'username': username})
app.register_blueprint(example_blueprint)
swag = Swagger(app)
if __name__ == "__main__":
app.run(debug=True)
您只需在引用端点时添加蓝图名称。蓝图创建名称空间。以下示例。有用的提示:使用app.logger.info(url_for('hello1'))
调试端点问题 - 它显示非常有用的错误消息,如Could not build url for endpoint 'hello1'. Did you mean 'api_bp.hello1' instead?
。
from flask import Flask, Blueprint, url_for
from flask_restful import Api, Resource
from flasgger import Swagger, swag_from
app = Flask(__name__)
api_blueprint = Blueprint('api_bp', __name__)
api = Api(api_blueprint)
class Hello(Resource):
@swag_from('hello1.yml', endpoint='api_bp.hello1')
@swag_from('hello2.yml', endpoint='api_bp.hello2')
def get(self, user=''):
name = user or 'stranger'
resp = {'message': 'Hello %s!' % name}
return resp
api.add_resource(Hello, '/hello', endpoint='hello1')
api.add_resource(Hello, '/hello/<string:user>', endpoint='hello2')
app.register_blueprint(api_blueprint)
swagger = Swagger(app)
app.run(debug=True)
swag_from函数有一些错误来解析文件路径。你可以使用doc string首先在get()中定义api。 flasgger将解析像get,post这样的MethodView()方法。
似乎flasgger不起作用或没有适当的支持蓝色打印样式Flask定义(尚)。我使用https://github.com/rantav/flask-restful-swagger,效果很好!