如何从模型中获取值并在控制器中显示

Question

我在codeigniter中创建一个站点，这是我的控制器，模型和视图：

控制器：

function checking()
 {
 $email=$this->input->post('email');
 $this->load->model('login_model');
 $data['dbemail']=$this->login_model->email();// assign your value to CI variable  
 $this->load->view('home', $data); //passing your value to view
 }

模型：

public function email()
 {
   $query = $this->db->query("SELECT email FROM change_password");
   $result = $query->result_array();
   return $result;
 }

视图：

foreach ( $dbemail as $new_dbemail )
   {
      echo $new_dbemail['database_field'];//in here you can get your table header. 
     //Ex if your table has name field and you need to sho it you can use $new_dbemail['name'] 
    }

但我想在我的控制器中获取$ new_dbemail ['name']，我怎样才能在控制器中获取$ new_dbemail ['name']的值而不是查看???

Answer 1

为此...您必须将数据提取到row_array中，而不是在Model中的result_array中。

调节器

function checking()
{
$email=$this->input->post('email');
$this->load->model('login_model');
$data['dbemail']=$this->login_model->email();  
$database_field = $data['dbemail']['database_field']; //to get result in controller
$date['database_field'] = $data['dbemail']['database_field']; //to get result in view
$this->load->view('home', $data);
}

模型

public function email()
{
$query = $this->db->query("SELECT email FROM change_password");
return $query->row_array();   
}

视图

<p> Database Field value : <?=$database_field;?></p>

Answer 2

你在变量中调用模型： -

$data['dbemail']=$this->login_model->email();

因此，您将获得从数据库中获取的结果。比将此变量数据传递给View。

$this->load->view('home', $data);

因此，您已经拥有了从存储在$ data中的模型中获取的控制器中的值。

您可以使用查看$ data的值

echo "<pre>";
print_r($data); 

它将显示您正在接收的数据

Answer 3

试试这样......

在控制器......

function checking()
 {
 $email=$this->input->post('email');
 $this->load->model('login_model');
 $dbemail=$this->login_model->email();//array containing all emails
 //For each loop here for displaying emails
 foreach($dbemail as $email){
   $mail = $email; //assigning to variable
   echo $mail."<br/>";//displaying email
   }

 $data['dbemail'] = $dbemail;//for passing to view
 $this->load->view('home', $data); //passing your value to view
 }

Answer 4

首先，您需要从模型中的数据库中获取名称。更改查询行：

$query = $this->db->query("SELECT name, email FROM change_password");

然后要使用控制器中的名称数据，您可以尝试这样做：

function checking()
{
   $email=$this->input->post('email');
   $this->load->model('login_model');
   $data['dbemail']=$this->login_model->email();
   $name = $data['dbemail']['name']; // example usage to retrieve name in controller
   $this->load->view('home', $data); 
}

现在名称数据在控制器中以$name的形式提供。

Answer 5

控制器：

public function checking()
 {
 $email=$this->input->post('email');
 $this->load->model('login_model');
 $data['dbemails']=$this->login_model->email(); 
 $this->load->view('home', $data); //passing your value to view
} 

模型

public function email()
{
$this->db->select("email"); // the row of the table you want to select.
$this->db->get('change_password'); //table name. you can still use your query, its just much neat when you use a specific query builder. 
$result = $this->result(); //giving you a result of type object
return $result;
} 

视图

foreach ( $dbemails as $dbemail )
 {
  echo $dbemail->email; // the '->' will be the identifier of which row you want to get or display, i assume its email beacause you specify it in the model. 
} 

希望这是你想要的。