如何将此代码简化为自动执行此操作的函数？

Question

我有这行代码：

        int[][] coordinates = new int[][]{{0, 0}, {1, 0}, {0, 1}, {-1, 0}, {0, -1}};
        if (yg.radius == 1) {
            coordinates = new int[][]{{0, 0}, {1, 0}, {0, 1}, {-1, 0}, {0, -1}};
        } else if (yg.radius == 2) {
            coordinates = new int[][]{{0, 0}, {1, 0}, {0, 1}, {-1, 0}, {0, -1}, {1, 1}, {-1, 1}, {-1, -1}, {1, -1}};
        } else if (yg.radius == 3) {
            coordinates = new int[][]{{0, 0}, {1, 0}, {0, 1}, {-1, 0}, {0, -1}, {1, 1}, {-1, 1}, {-1, -1}, {1, -1}, {2, 0}, {0, 2}, {-2, 0}, {0, -2}};
        } else if (yg.radius == 4) {
            coordinates = new int[][]{{0, 0}, {1, 0}, {0, 1}, {-1, 0}, {0, -1}, {1, 1}, {-1, 1}, {-1, -1}, {1, -1}, {2, 0}, {0, 2}, {-2, 0}, {0, -2}, {2, 2}, {-2, 2}, {-2, -2}, {2, -2}};
        } else if (yg.radius == 5) {
            coordinates = new int[][]{{0, 0}, {1, 0}, {0, 1}, {-1, 0}, {0, -1}, {1, 1}, {-1, 1}, {-1, -1}, {1, -1}, {2, 0}, {0, 2}, {-2, 0}, {0, -2}, {2, 2}, {-2, 2}, {-2, -2}, {2, -2}, {3, 0}, {0, 3}, {-3, 0}, {0, -3}};
        } else if (yg.radius == 6) {
            coordinates = new int[][]{{0, 0}, {1, 0}, {0, 1}, {-1, 0}, {0, -1}, {1, 1}, {-1, 1}, {-1, -1}, {1, -1}, {2, 0}, {0, 2}, {-2, 0}, {0, -2}, {2, 2}, {-2, 2}, {-2, -2}, {2, -2}, {3, 0}, {0, 3}, {-3, 0}, {0, -3}, {3, 3}, {-3, 3}, {-3, -3}, {3, -3}};
        } else if (yg.radius == 7) {
            coordinates = new int[][]{{0, 0}, {1, 0}, {0, 1}, {-1, 0}, {0, -1}, {1, 1}, {-1, 1}, {-1, -1}, {1, -1}, {2, 0}, {0, 2}, {-2, 0}, {0, -2}, {2, 2}, {-2, 2}, {-2, -2}, {2, -2}, {3, 0}, {0, 3}, {-3, 0}, {0, -3}, {3, 3}, {-3, 3}, {-3, -3}, {3, -3}, {4, 0}, {0, 4}, {-4, 0}, {0, -4}};
        } else if (yg.radius == 8) {
            coordinates = new int[][]{{0, 0}, {1, 0}, {0, 1}, {-1, 0}, {0, -1}, {1, 1}, {-1, 1}, {-1, -1}, {1, -1}, {2, 0}, {0, 2}, {-2, 0}, {0, -2}, {2, 2}, {-2, 2}, {-2, -2}, {2, -2}, {3, 0}, {0, 3}, {-3, 0}, {0, -3}, {3, 3}, {-3, 3}, {-3, -3}, {3, -3}, {4, 0}, {0, 4}, {-4, 0}, {0, -4}, {4, 4}, {-4, 4}, {-4, -4}, {4, -4}};
        }
        for (int[] coordinate : coordinates) {
            Hit(coordinate[0], coordinate[1], yg.damage);
        }

（是的，这都是我手写的😭） 现在，问题是。我怎样才能自动做到这一点？我的意思是我不想将这一切手动写入 yg.radius 20。

我期望有一个函数将半径作为参数，并返回坐标数组。 也许我甚至做错了，我只需要一个数组，为我提供圆形效果中的像素。 预先感谢！

Answer 1

下面可以帮助你，你可以尝试一下吗？

int[][] getCoordinatesInCircle(int radius) {
int[][] coordinates = new int[4 * radius * radius + 1][];  // Allocate space for all coordinates
int index = 0;

for (int x = -radius; x <= radius; x++) {
    for (int y = -radius; y <= radius; y++) {
        if (x * x + y * y <= radius * radius) {  // Check if within circle
            coordinates[index++] = new int[]{x, y};
        }
    }
}
return coordinates; }

#happycoding #ng