如何检测UITableViewCellStyleSubtitle样式中UITableViewCell对象的UIImageView上的触摸

Question

我正在使用UITableViewCell风格的UITableViewCellStyleSubtitle对象（即左侧的图像视图，粗体的文本标签和详细文本标签下）来创建我的表格。现在我需要检测UIImageView上的触摸，还要知道单击图像视图的索引路径/单元格。我试过用

cell.textLabel.text = @"Sometext";
NSString *path = [[NSBundle mainBundle] pathForResource:@"emptystar1" ofType:@"png"];
UIImage *theImage = [UIImage imageWithContentsOfFile:path];
cell.imageView.image = theImage;
cell.imageView.userInteractionEnabled = YES; 

但它不起作用。每当点击图像时，都会调用didSelectRowAtIndexPath:。我不想创建一个单独的UITableViewCell并添加一个自定义按钮。有没有办法检测UIImageView本身的触摸？

Answer 1

在你的cellForRowAtIndexPath方法中添加此代码

cell.imageView.userInteractionEnabled = YES;
cell.imageView.tag = indexPath.row;

UITapGestureRecognizer *tapped = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(myFunction:)];
tapped.numberOfTapsRequired = 1;
[cell.imageView addGestureRecognizer:tapped];   
[tapped release];

然后检查点击了哪个imageView，检查selector方法中的标志

-(void)myFunction :(id) sender
{
    UITapGestureRecognizer *gesture = (UITapGestureRecognizer *) sender;
    NSLog(@"Tag = %d", gesture.view.tag);
}

Answer 2

目前已接受的解决方案在iOS 5.0中被破坏。该错误导致图像视图的手势识别器永远不会被触发。通过对官方开发人员论坛的研究，我发现这是iOS 5.0中的已知错误。它是由内部实现导致-gestureRecognizerShouldBegin:返回NO。当您将手势识别器的委托设置为自定义UITableViewCell子类本身时，会出现该错误。

修复是在手势识别器的委托中覆盖-gestureRecognizerShouldBegin:并返回YES。应该在iOS 5.x的未来版本中修复此错误。只要您没有使用新的UITableViewCell复制/粘贴API，这只是安全的。

- (BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer
{
    return YES;
}

Answer 3

对于Swift，在您的cellForRowAtIndexPath方法中添加此代码

cell.imageView?.userInteractionEnabled = true
cell.imageView?.tag = indexPath.row

var tapped:UITapGestureRecognizer = UITapGestureRecognizer(target: self, action: "TappedOnImage:")
tapped.numberOfTapsRequired = 1
cell.imageView?.addGestureRecognizer(tapped)

然后检查单击了哪个imageView，检查选择器方法中的标志

func TappedOnImage(sender:UITapGestureRecognizer){
    println(sender.view?.tag)
}

Answer 4

你可以做的一种方法是从你的图像创建一个UIImageView并添加一个手势识别器。请参阅下面的示例

//Create ImageView
UIImageView *theImageView = [[UIImageView alloc] initWithImage:[UIImage imageNamed:@"emptystar1.png"]];
theImageView.userInteractionEnabled = YES;

//Add Gesture Recognizer
UITapGestureRecognizer *tapped = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(imageSelectedInTable)];
tapped.numberOfTapsRequired = 1;
[theImageView addGestureRecognizer:tapped];
[cell addSubview:theImageView];

//Memory Cleanup
[tapped release];
[theImageView release];

-(void)imageSelectedInTable
{
    NSLog(@"Selected an Image");
}

但是，你现在必须更多地布置你的单元格，因为你不能简单地使用UIImageView的UITableViewCell属性，因为它只是readonly。

Answer 5

只有在我的情况下，我必须回答从NSFetchedResultsController检索到的表格单元的图像文件上的轻击手势的附加信息，所以我们需要indexPath而不是行，所以我决定使用图像轻敲自己而不是行信息。我为图像定义了一个变量：

var imgSelected: UIImageView? = nil

我将手势识别器添加到imageView（imgZona）：

public override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCellWithIdentifier(Storyboard.CellReuseIdentifier, forIndexPath: indexPath) as! ZonasTableViewCell
    let zona = fetchedResultsController.objectAtIndexPath(indexPath) as! Zona

    cell.infoZona = zona

    let tapGestureRecognizer = UITapGestureRecognizer(target:self, action:Selector("imageTapped:"))

    cell.imgZona?.addGestureRecognizer(tapGestureRecognizer)
    cell.imgZona?.userInteractionEnabled = true

    return cell
}

在“imageTapped”方法中，我检索了图像并保存到变量“imgSelected”：

func imageTapped(sender: UITapGestureRecognizer) {

    imgSelected = sender.view as? UIImageView
    self.performSegueWithIdentifier("MuestraImagen", sender: self)
}

最后，在“prepareForSegue”方法中，我发送了viewController专用的图像来显示被点击的图像：

override public func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
    if let identifier = segue.identifier {
        switch identifier {
        case "MuestraImagen":
            if let vc = segue.destinationViewController as? MuestraImagenViewController {
                if imgSelected != nil {
                    if let img = imgSelected!.image {
                        vc.imgPuente = img
                    }
                }
            }
        default: break
        }
    }
}

Answer 6

这个问题是：

• 将ImageView添加到TableViewCell中
• 事件单击进入ImageView不同于事件单击进入TableViewCell

- >以下代码可以正常使用我：

cell.imageView.image = [UIImage imageNamed:@"my_image.png"];
[cell.imageView setUserInteractionEnabled:YES];
UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(singleTapGestureCaptured:)];    
[cell.imageView addGestureRecognizer:singleTap];

和“singleTapGestureCaptured”功能

- (void)singleTapGestureCaptured:(UITapGestureRecognizer*)gesture{
    NSLog(@"Left Image clicked");
}