如何在MySQL的当月第一天和当前日期之间进行选择?

问题描述 投票:49回答:13

我需要在当月的第一天和当天之间从MySQL数据库中选择数据。

select*from table_name 
where date between "1st day of current month" and "current day"

有人可以提供此查询的工作示例吗?

mysql date get
13个回答
124
投票
select * from table_name 
where (date between  DATE_ADD(LAST_DAY(DATE_SUB(CURDATE(), interval 30 day), interval 1 day) AND CURDATE() )

或更好 :

select * from table_name 
where (date between  DATE_FORMAT(NOW() ,'%Y-%m-01') AND NOW() )

0
投票
SELECT date_sub(current_date(),interval dayofmonth(current_date())-1 day) as first_day_of_month;

0
投票

我用过这个select DATE_ADD(DATE_SUB(LAST_DAY(now()), INTERVAL 1 MONTH),INTERVAL 1 day) first_day , LAST_DAY(now()) last_day, date(now()) today_day


0
投票

我有一些类似的要求 - 对find first day of the month但基于用户在他们的个人资料页面中选择的year end month

问题陈述 - 找到用户在其财政年度完成的所有txnsFinancial year是使用year end月值确定的,其中month可以是任何有效月份 - 1 for Jan2 for Feb3 for Mar,.... 12 for Dec

对于一些客户financial year ends在March和一些观察它在December

Scenarios - (Today is `08 Aug, 2018`)
   1. If `financial year` ends on `July` then query should return `01 Aug 2018`.
   2. If `financial year` ends on `December` then query should return `01 January 2018`.
   3. If `financial year` ends on `March` then query should return `01 April 2018`.
   4. If `financial year` ends on `September` then query should return `01 October 2017`.

最后,下面是查询。 -

select @date := (case when ? >= month(now()) 
then date_format((subdate(subdate(now(), interval (12 - ? + month(now()) - 1) month), interval day(now()) - 2 day)) ,'%Y-%m-01')
else date_format((subdate(now(), interval month(now()) - ? - 1 month)), '%Y-%m-01') end)

其中?year end月(值从1到12)。


-1
投票
SET @date:='2012-07-11';
SELECT date_add(date_add(LAST_DAY(@date),interval 1 DAY), 
       interval -1 MONTH) AS first_day

26
投票

我正在寻找类似的查询,我需要在查询中使用一个月的第一天。 last_day功能对我不起作用,但DAYOFMONTH派上用场。

因此,如果有人正在寻找相同的问题,以下代码将返回当月第一天的日期。

SELECT DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY);

将日期列与该月的第一天进行比较:

select * from table_name where date between 
DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY) and CURRENT_DATE

5
投票
select * from table_name 
where `date` between curdate() - dayofmonth(curdate()) + 1
                 and curdate()

SQLFiddle example


3
投票

我使用了以下查询。它过去对我很有用。

select date(now()) - interval day(now()) day + interval 1 day

2
投票

试试这个 :

SET @StartDate = DATE_SUB(DATE(NOW()),INTERVAL (DAY(NOW())-1) DAY);
SET @EndDate = ADDDATE(CURDATE(),1);
select * from table where (date >= @StartDate and date < @EndDate);

1
投票

mysql当前月份和当前年份的完整解决方案,它也正确地使用了索引:)

-- Current month
SELECT id, timestampfield 
  FROM table1
 WHERE timestampfield >= DATE_SUB(CURRENT_DATE, INTERVAL DAYOFMONTH(CURRENT_DATE)-1 DAY)
   AND timestampfield <=  LAST_DAY(CURRENT_DATE);

-- Current year
SELECT id, timestampfield 
  FROM table1
 WHERE timestampfield >= DATE_SUB(CURRENT_DATE, INTERVAL DAYOFYEAR(CURRENT_DATE)-1 DAY)
   AND timestampfield <=  LAST_DAY(CURRENT_DATE);

1
投票
select * from table
where date between 
(date_add (CURRENT_DATE, INTERVAL(1 - DAYOFMonth(CURRENT_DATE)) day)) and current_date;

1
投票
select * from <table>
where <dateValue> between last_day(curdate() - interval 1 month + interval 1 day)
                  and curdate();

0
投票

一种不太正统的方法可能是

SELECT * FROM table_name 
WHERE LEFT(table_name.date, 7) = LEFT(CURDATE(), 7)
  AND table_name.date <= CURDATE();

作为一个月的第一个和现在之间的日期相当于本月的日期,现在之前。不过,我确实觉得这比其他方法更容易。

© www.soinside.com 2019 - 2024. All rights reserved.