Tkinter标签没有被破坏

问题描述 投票:0回答:2

我写了一些调查问卷,单击下一步或复选按钮不会破坏问题。有时它起作用,有时却不起作用。真的很奇怪这些问题将放在旧的问题之上。这就像一堆问题,真是令人讨厌。

def myLabeldestroy(self):
    myLabel01.destroy()
def checkAnswer(self):
    ###Creation of random integers
    self.iniRand()
    ###Delete myLabel
    self.myLabeldestroy()
    self.mylabel(self.theories[self.qList][self.index][self.zero], 0, 1)
    ###Check whether answer is in used list or not
    if self.theories[self.qList] not in self.usedTheories:
        if self.gs[self.index][self.zero] not in self.used:
            ###Correct answer  
            self.myEntry.get() == str(self.theories[self.qList][self.index][self.one])
            self.used.append(self.gs[self.index][self.zero])
            self.mylabel(self.answer[self.answerIndex], 2, 1)
            self.counter += self.one
            ###Point counter
            self.mylabel("Point counter " + str(self.counter), 4, 1)
        ###Wrong answer
        else:
            self.mylabel(self.reply[self.answerIndex], 2, 1)
def nextAnswer(self):
    ###Creation of random integers
    self.iniRand()
    ###Delete myLabel
    self.myLabeldestroy()
    self.mylabel(self.theories[self.qList][self.index][self.zero], 0, 1)
    ###Check whether answer is in used list or not
    if self.theories[self.qList] not in self.usedTheories:
        if self.gs[self.index][self.zero] not in self.used:
            self.used.append(self.gs[self.index][self.zero])
            self.counter -= self.one
            ###Point counter
            self.mylabel("Point counter " + str(self.counter), 4, 1)
python tkinter label
2个回答
0
投票

您可能需要在破坏按钮后调用frame.refresh()


0
投票

[我可以建议您使用其他方法。如果您使用的是.pack()方法,请使用pack_forget()或grid_forget()(如果您使用的是.grid()。请从here中了解更多信息。

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