我用c写的，为什么我的代码没有运行？我在 ss 上画出了错误

Question

我不明白为什么这条消息出现在我的终端中：

请输入您要计算百分比的第一个变量，不带任何空格： 莫兰戈斯 PS C:\Users\TechnoStoreReparacoe\Desktop>

这是完整的代码：

#include <stdio.h>
#include <string.h>

int main (){
    
    char name1[25] ;
    char name2[25] ;
    char name3[25];
    char name4[25];
    char name5[25];

    int value1 ;
    int value2 ;
    int value3 ;
    int value4 ;
    int value5 ;
    
    
    printf ("Hello mortal, this program allows you to calculate percentages of five parts that are the only components of the whole.\n");
    
    printf ("\nPlease enter your 1st variable that you want to calculate the percentage of without any spaces:\n");
    fgets (name1, 25, stdin);
    printf ("\nPlease enter the value of %s:\n", name1[25]);
    scanf ("%i", &value1);
    
    printf ("\nPlease enter your 2nd variable that you want to calculate the percentage of without any spaces:\n");
    fgets (name2, 25, stdin);
    printf ("\nPlease enter the value of %s:\n", name2[25]);
    scanf ("%i", &value1);

    
    printf ("\nPlease enter your 3rd variable that you want to calculate the percentage of without any spaces:\n");
    fgets (name3, 25, stdin);
    printf ("\nPlease enter the value of %s:\n", name3[25]);
    scanf ("%i", &value1);


    printf ("\nPlease enter your 4th variable that you want to calculate the percentage of without any spaces:\n");
    fgets (name4, 25, stdin);
    printf ("\nPlease enter the value of %s:\n", name4[25]);
    scanf ("%i", &value1);


    
    printf ("\nPlease enter your 5th variable that you want to calculate the percentage of without any spaces:\n");
    fgets (name5, 25, stdin);
    printf ("\nPlease enter the value of %s:\n", name5[25]);
    scanf ("%i", &value1);


    return 0;
}

我正在制作一个概率查找程序，非常简单。 用户输入变量名称和相应的数值。 这是我的第一个程序，我不明白为什么代码运行不好

Answer 1

printf()

期望得到

char *

，而不是

char

name1[25]

中的

printf()

是数组

name1[]

的第25个（从0开始）元素。

char

位于数组

name[]

之外，无法读取。

"%s"

需要一个匹配的指针，即

char *

。

char name1[25] ;
// printf ("\nPlease enter the value of %s:\n", name1[25]);
printf ("\nPlease enter the value of %s:\n", name1);