我正在尝试解决此问题
执行时
php bin/console doctrine:schema:update --dump-sql
我正在
In SchemaException.php line 108:
The table with name 'chris_test_sonata.page__block' already exists.
显然,该表在我的数据库中不存在。为确保它与缓存无关,我什至对刚创建的新数据库进行了操作,结果是相同的。
当我在项目中搜索page__block时,我只会找到此映射
/**
* @ORM\Entity
* @ORM\Table(name="page__block")
* @ORM\HasLifecycleCallbacks
*/
class SonataPageBlock extends BaseBlock
因此该表不应有其他映射。
我也有一个block.orm.xml
<?xml version="1.0" encoding="utf-8"?>
<doctrine-mapping xmlns="http://doctrine-project.org/schemas/orm/doctrine-mapping" xsi="http://www.w3.org/2001/XMLSchema-instance" schemaLocation="http://doctrine-project.org/schemas/orm/doctrine-mapping http://doctrine-project.org/schemas/orm/doctrine-mapping.xsd">
<!--
This file has been generated by the EasyExtends bundle ( https://sonata-project.org/easy-extends )
References :
xsd : https://github.com/doctrine/doctrine2/blob/master/doctrine-mapping.xsd
xml mapping : http://www.doctrine-project.org/projects/orm/2.0/docs/reference/xml-mapping/en
association mapping : http://www.doctrine-project.org/projects/orm/2.0/docs/reference/association-mapping/en
-->
<entity
name="App\Application\Sonata\PageBundle\Entity\Block"
table="page__block"
repository-class="Doctrine\ORM\EntityRepository">
<id name="id" type="integer" column="id">
<generator strategy="AUTO"/>
</id>
</entity>
</doctrine-mapping>
还有其他一些情况,但都在dev.log中
而且我在symfony dev / pools的缓存文件中也有此文件
<?php
namespace Symfony\Component\VarExporter\Internal;
return $getExpiry ? PHP_INT_MAX : Hydrator::hydrate(
$o = [
clone (($p = &Registry::$prototypes)['Doctrine\\ORM\\Mapping\\Entity'] ?? Registry::p('Doctrine\\ORM\\Mapping\\Entity')),
clone ($p['Doctrine\\ORM\\Mapping\\Table'] ?? Registry::p('Doctrine\\ORM\\Mapping\\Table')),
clone ($p['Doctrine\\ORM\\Mapping\\HasLifecycleCallbacks'] ?? Registry::p('Doctrine\\ORM\\Mapping\\HasLifecycleCallbacks')),
],
null,
[
'stdClass' => [
'name' => [
1 => 'page__block',
],
],
],
[
$o[0],
$o[1],
$o[2],
],
[]
);
我不知道它有什么问题以及为什么映射不起作用。
Block
的page__block
实体,并且创建了具有相同表名的新实体SonataPageBlock
。如果更改SonataPageBlock
的表名,一切都很好,但是它将是数据库中的2个不同的表。