我正在尝试创建一个下载文件的链接,该文件已上传。
models.朋友
class Comentario (models.Model):
archivo = models.FileField(upload_to='media', null=True, blank=True)
settings.朋友
MEDIA_ROOT=os.path.join(BASE_DIR, 'media')
MEDIA_URL='/media/'
template.html
<a href="{{ MEDIA_URL }} {{detail.archivo.url}}" download>Descargar</a>
views.朋友
def ComentarioListar(request):
form2 = ComentarioForm(request.POST or None, request.FILES or None)
if request.method == 'POST' and form2.is_valid():
form2.instance.autor = request.user
form2.save()
return HttpResponseRedirect('http://127.0.0.1:8000/home/listar')
objects= Comentario.objects.filter(tag__in=bb).exclude(autor__id=request.user.id)[:5]
return render(request, 'home/comentario_listar.html', {'objects': objects, 'form2':form2})
URLs.朋友
urlpatterns = [
url(r'^download/(?P<filename>.+)$', login_required(views.download), name='download')]
当我点击下载链接时,它不会下载保存在'media'文件夹中的.jpg。路径是否错误指定?有必要为此创建一个特殊视图吗?
谢谢您的回答
您的问题是您将Comentario对象的Queryset作为“对象”传递给您的模板,但您在模板中根本没有引用“对象”。
下面是一个示例,说明如何为“对象”Queryset中的每个对象提取URL列表。在这里,我们遍历'对象'Queryset中的每个对象,并将其archivo.url拉出到模板中:
comentario_listar.html
{% for object in objects %}
<a href="{{ object.archivo.url }}">Descargar</a>
{% endfor %}
请注意,如果您愿意,您还可以将comentario_listar.html传递给单个对象,并像这样呈现该对象的URL:
views.朋友
def ComentarioListar(request):
form2 = ComentarioForm(request.POST or None, request.FILES or None)
if request.method == 'POST' and form2.is_valid():
form2.instance.autor = request.user
form2.save()
return HttpResponseRedirect('http://127.0.0.1:8000/home/listar')
// Create a variable called 'detail' that references just one Comentario object, and pass it to the comentario_listar.html template
detail = Comentario.objects.all()[0]
return render(request, 'home/comentario_listar.html', {'detail': detail, 'form2':form2}
comentario_listar.html
<a href="{{detail.archivo.url}}" download>Descargar</a>