iOS 10 beta 上的通讯录崩溃问题

问题描述 投票:0回答:9

当点击地址簿中的任何联系人(在我的应用程序内)时,它在 iOS 10 beta 上崩溃,但在 iOS 9 版本上工作正常;

这是崩溃日志

*** Terminating app due to uncaught exception 'CNPropertyNotFetchedException', reason: 'A property was not requested when contact was fetched.'
*** First throw call stack:
(0x1cf11a07 0x1c62af63 0x1cf1194d 0x246f0f4f 0x246c6a71 0x1ce355eb 0x1ce2e19b 0x246c69cf 0x246c6883 0x25e4a375 0x2538f283 0x254204ef 0x25420bb1 0xe9da97 0xe9da83 0xea2321 0x1cecf18f 0x1cecd477 0x1ce1e6bd 0x1ce1e549 0x1e54ebfd 0x21f961e3 0x21f90947 0x966c9 0x1ca9e507)
libc++abi.dylib: terminating with uncaught exception of type NSException

这是在我的应用程序中打开地址簿的代码:

-(void)showContactPicker {
__weak RecieverSelectorViewController *weakSelf = self;
    ABPeoplePickerNavigationController* picker = [[ABPeoplePickerNavigationController alloc] init];
    picker.peoplePickerDelegate = self;
    picker.modalPresentationStyle = UIModalPresentationFullScreen;
    picker.modalTransitionStyle = UIModalPresentationPopover;
    [self presentViewController:picker
                       animated:YES
                     completion:^{
                         [weakSelf hideLoadingAnimation];

                         // animation to show view controller has completed.
                     }];
}



- (void)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker didSelectPerson:(ABRecordRef)person property:(ABPropertyID)property identifier:(ABMultiValueIdentifier)identifier {
    [self setSelectedPerson:person];
}

- (void)peoplePickerNavigationController:(ABPeoplePickerNavigationController*)peoplePicker didSelectPerson:(ABRecordRef)person {
    [self setSelectedPerson:person];
}

-(void)setSelectedPerson:(ABRecordRef)person {


    NSString *contactName = CFBridgingRelease(ABRecordCopyCompositeName(person));

    ABMultiValueRef phoneRecord = ABRecordCopyValue(person, kABPersonPhoneProperty);
    CFStringRef phoneNumber = ABMultiValueCopyValueAtIndex(phoneRecord, 0);

    self.isSenderReciever = NO;

    NSString *phone = [PorterUtils
                       extraLast10DigitsFromDigitString:[PorterUtils
                                                         extractNumberFromText:(__bridge_transfer NSString *)phoneNumber]];




    //Handling Social Media Contacts - Crash

    if(contactName.length>0 && phone.length>0){

      [self setRecieverName:contactName
                   number:phone];
       CFRelease(phoneRecord);
    }

}

仅在 iOS 10 公开测试版上崩溃。

ios contacts addressbook ios10
9个回答
12
投票

尝试使用CNContactPickerViewController(iOS9及以上):

添加ContactsUI.framework,导入框架,声明委托CNContactPickerDelegate。

实现它(在 Objective-C 中):

CNContactPickerViewController *peoplePicker = [[CNContactPickerViewController alloc] init];
    peoplePicker.delegate = self;
    NSArray *arrKeys = @[CNContactPhoneNumbersKey]; //display only phone numbers
    peoplePicker.displayedPropertyKeys = arrKeys;
    [self presentViewController:peoplePicker animated:YES completion:nil];

代表示例:

- (void)contactPicker:(CNContactPickerViewController *)picker didSelectContactProperty:(CNContactProperty *)contactProperty{ 

    CNPhoneNumber *phoneNumber = contactProperty.value;
    NSString *phoneStr = phoneNumber.stringValue;
}

11
投票

地址簿 API 在 iOS 9 中已被弃用,取而代之的是更加面向对象的联系人框架

不要使用 ABPeoplePickerViewController,而是移至 CNContactPickerViewController


6
投票

检查您是否提供了有效的密钥,例如

@[CNContactFamilyNameKey, CNContactGivenNameKey, CNContactPhoneNumbersKey, CNContactEmailAddressesKey]

当他们向 CNContact 对象请求时。

例如:如果您需要调用 contact.emailAddresses,则必须从 (CNContactEmailAddressesKey) 数组提供。


5
投票

将“隐私 - 联系人使用说明”添加到您的 info.plist 。

苹果论坛中也提出了同样的问题。 GWesley 的原始答案如下。

苹果论坛帖子


4
投票

iOS 10 不允许访问联系人,直到我们提到为什么我们使用它。打开你的 plist 作为源代码,在 dict 下添加以下代码现在再次运行它。

<key>NSContactsUsageDescription</key>
<string>$(PRODUCT_NAME) uses Contact</string>

1
投票

IOS 10 现在需要用户权限才能访问媒体库、照片、 相机和其他类似的硬件。解决这个问题的方法是添加 将他们的密钥放入 info.plist 中,并为用户提供我们的描述 使用他们的数据,iOS已经需要访问权限 麦克风、相机和媒体库较早(iOS6、iOS7),但自此 iOS10 如果您不提供说明原因,应用程序将会崩溃 正在请求许可。

您可以在 Info.plist 文件中指定所有 Cocoa Key 的列表

照片:

Key       :  Privacy - Photo Library Usage Description    
Value   :  $(PRODUCT_NAME) photo use

麦克风:

Key        :  Privacy - Microphone Usage Description    
Value    :  $(PRODUCT_NAME) microphone use

相机:

Key       :  Privacy - Camera Usage Description   
Value   :  $(PRODUCT_NAME) camera use

1
投票

斯威夫特3

// This example allows the display and selection of email addresses only.
if #available(iOS 9.0, *) {
    let picker = CNContactPickerViewController()
    let arrKeys = [CNContactEmailAddressesKey] // array of properties to display
    picker.displayedPropertyKeys = arrKeys
    picker.delegate = self
    present(picker, animated: true, completion: nil)
}

代表示例

    @available(iOS 9.0, *)
    func contactPicker(_ picker: CNContactPickerViewController, didSelect contactProperty: CNContactProperty) {
        let emailAddress = contactProperty.value as? String     
    }

0
投票

首先在

NSContactsUsageDescription
中添加
info.plist
,然后将控制器呈现在AB请求访问块中,如下所示。

ABAddressBookRequestAccessWithCompletion(contactPicker, { success, error in
  if success {
    self.presentViewController(self.contactPicker, animated: true, completion: nil)
  }
})

0
投票

您可能忘记指定您获取的所有密钥。假设您在自定义

contact.middleName
映射中使用
ContactModel
,但忘记在请求中指定
CNContactMiddleNameKey

使用请求中的键获取联系人的示例:

    let keys = [
                    CNContactGivenNameKey as CNKeyDescriptor,
                    CNContactFamilyNameKey as CNKeyDescriptor,
                    CNContactMiddleNameKey as CNKeyDescriptor,
                    CNContactPhoneNumbersKey as CNKeyDescriptor,
                    CNContactImageDataKey as CNKeyDescriptor
                ]
                
                let request = CNContactFetchRequest(keysToFetch: keys)

                try store.enumerateContacts(with: request) { contact, _ in
                    let newContact = ContactModel(
                        id: contact.identifier,
                        name: contact.givenName + contact.middleName,
                        surname: contact.familyName,
                        image: contact.imageData,
                        numbers: contact.phoneNumbers.compactMap( { $0.value.stringValue } )
                    )
                    contacts.append(newContact)
                }
© www.soinside.com 2019 - 2024. All rights reserved.