这是我的代码:
<div [id]="id" class="modal fade" tabindex="-1">
<div class="modal-dialog modal-full">
<div class="modal-content">
<div class="modal-header bg-danger">
<h6 class="modal-title"</h6>
<button type="button" class="close" data-dismiss="modal">×</button>
</div>
<form #editViewForm="ngForm" (ngSubmit)="onSubmit()" id="editViewForm" autocomplete="off">
<div id="tabs" class="modal-body">
<!--Tabs Nav-->
<ul class="nav nav-tabs nav-tabs-highlight mb-0">
<li class="nav-item"><a href="#bordered-tab1" id="active_tab" class="nav-link active" data-toggle="tab">TAB 1</a></li>
<li class="nav-item"><a href="#bordered-tab2" class="nav-link" data-toggle="tab">TAB 2</a></li>
<li class="nav-item"><a href="#bordered-tab3" class="nav-link" data-toggle="tab" style="display:none;">TAB 3</a></li>
<li class="nav-item"><a href="#bordered-tab4" class="nav-link" data-toggle="tab">TAB 4</a></li>
</ul>
</div>
</form>
</div>
</div>
如何在每次打开这个模态时将TAB 1设置为打开,以防我在tab3上关闭模态我想要再次打开模态时TAB 1处于活动状态
我试过这个:
我在第一个标签上添加了这样的:active_tab
,所以我说了这样的话,当这个节目被调用时(模态是开放的)让我们设置两个classess,show和active,但是这个不幸的是不起作用...
show() {
alert("ok");
$('#active_tab' + this.id).addClass('active');
$('#active_tab' + this.id).addClass('show');
$('#' + this.id).modal('show');
}
谢谢你们干杯
请我们[ngClass] =“{'有效':tabName ==='tab1'}”
<ul class="nav nav-tabs nav-tabs-highlight mb-0">
<li class="nav-item"><a href="#bordered-tab1" class="nav-link" [ngClass]="{'active': tabName === 'tab1'}" data-toggle="tab">TAB 1</a></li>
<li class="nav-item"><a href="#bordered-tab2" [ngClass]="{'active': tabName === 'tab2'}" class="nav-link" data-toggle="tab">TAB 2</a></li>
<li class="nav-item"><a href="#bordered-tab3" [ngClass]="{'active': tabName === 'tab3'}" class="nav-link" data-toggle="tab" style="display:none;">TAB 3</a></li>
<li class="nav-item"><a href="#bordered-tab4" class="nav-link" data-toggle="tab" [ngClass]="{'active': tabName === 'tab4'}">TAB 4</a></li>
</ul>
并在组件的ngOnInt事件上,设置this.tabName ='tab1'
tabName: string;
ngOnInit() {
this.tabName = 'tab1'
}