这个问题在这里已有答案：
我有两个数组arr1和arr2我希望我的输出像1,2,3,4 ...如果我的arr1和arr2包含相同的数字但不幸的是我只得到一个匹配的例子如果我把var arr1 = [1,2,3,4,5,6,7,8,9,0]和var arr2 = [ 1,2,3,4,5]然后我希望我的输出像：
1,2,3,4,5
var i, j;
var arr1 = new Array(5);
var arr2 = new Array(5);
for (i = 0; i <= 4; i++) {
arr1[i] = parseInt(prompt("Enter The arr1 Element"));
}
for (i = 0; i <= 4; i++) {
arr2[i] = parseInt(prompt("Enter The Arr2 Element"));
}
var k;
var l;
for (k = 0; k < arr1.length; k++) {
for (l = 0; l < arr2.length; l++) {
if (arr1[k] == arr2[l]) {
document.getElementById("show").innerHTML = arr1[k];
}
continue;
}
}
<html>
<head>
<title>
Common In Array[]
</title>
</head>
<body>
<p id="show"></p>
</body>
</html>然后我希望我的输出像：1,2,3,4,5
您只使用赋值运算符=设置一个值。
document.getElementById("show").innerHTML = arr1[k];
您需要在数组中推送值，然后在用,分隔后立即显示它们
var output = [];
for (k = 0; k < arr1.length; k++) {
for (l = 0; l < arr2.length; l++) {
if (arr1[k] == arr2[l]) {
output.push(arr1[k]);
}
}
}
document.getElementById("show").innerHTML = output.join(",");
演示
var i, j;
var arr1 = new Array(5);
var arr2 = new Array(5);
for (i = 0; i <= 4; i++) {
arr1[i] = parseInt(prompt("Enter The arr1 Element"));
}
for (i = 0; i <= 4; i++) {
arr2[i] = parseInt(prompt("Enter The Arr2 Element"));
}
var k;
var l;
var output = [];
for (k = 0; k < arr1.length; k++) {
for (l = 0; l < arr2.length; l++) {
if (arr1[k] == arr2[l]) {
output.push(arr1[k]);
}
}
}
document.getElementById("show").innerHTML = output.join(",");<p id="show"></p>看一下这个。您不需要非常复杂的逻辑来实现您想要的
var arr1 = [1,2,3,4,5,6,7,8,9,0];
var arr2 = [ 1,2,3,4,5];
let res = [];
if(arr1.length >= arr2.length) {
res = arr1.filter(a => arr2.find(o => o === a));
} else {
res = arr2.filter(a => arr1.find(o => o === a));
}
console.log(res)
document.getElementById("show").innerHTML = res;<p id="show"></p>试试这个：
var outputstring = "";
for (k = 0; k < arr1.length; k++) {
for (l = 0; l < arr2.length; l++) {
if (arr1[k] == arr2[l]) {
outputstring += arr1[k] + ",";
}
continue;
}
}
document.getElementById("show").innerHTML = outputstring;
你可以使用filter方法并比较两个数组......
let arr1 = [1,2,3,4,5];
let arr2 = [1,2,3,6,7];
let result = arr1.filter((element)=>arr2.includes(element));
console.log(result);var array1 = [1,2,3,4,5,6,7,8,9,0];
var array2 = [1,2,3,4,5];
var results = array1.filter(function(item) {
return array2.indexOf(item) !== -1;
});
console.log(results);