什么是最优雅的一天结束的方式（日期时间）？ 我目前正在编写一些报告代码，以允许用户选择指定日期范围。它的工作方式（简化）是： 用户（选项）指定一年。 用户（可选）指定...

Question

用户（可选）指定一个月。

用户（可选）每天指定。

这里是一个代码段，以及描述我要做什么的评论：

from datetime import datetime, timedelta

# ...

now = datetime.now()
start_time = now.replace(hour=0, minute=0, second=0, microsecond=0)
stop_time = now
# If the user enters no year, month, or day--then we'll simply run a
# report that only spans the current day (from the start of today to now).

if options['year']:
    start_time = start_time.replace(year=options['year'], month=0, day=0)
    stop_time = stop_time.replace(year=options['year'])
    # If the user specifies a year value, we should set stop_time to the last
    # day / minute / hour / second / microsecond of the year, that way we'll
    # only generate reports from the start of the specified year, to the end
    # of the specified year.

if options['month']:
    start_time = start_time.replace(month=options['month'], day=0)
    stop_time = stop_time.replace(month=options['month'])
    # If the user specifies a month value, then set stop_time to the last
    # day / minute / hour / second / microsecond of the specified month, that
    # way we'll only generate reports for the specified month.

if options['day']:
    start_time = start_time.replace(day=options['day'])
    stop_time = stop_time.replace(day=options['day'])
    # If the user specifies a day value, then set stop_time to the last moment of
    # the current day, so that reports ONLY run on the current day.

• 我正在试图找到上面写代码的最优雅的方法 - 我一直在尝试找到一种使用TimeDelta的方法，但似乎无法弄清楚。任何建议将不胜感激。
为适当的一年，月或一天设置

stop_time

，然后减去一年，一个月或一天 start_time

使用

timedelta(microseconds=1)

可以简化您的代码。 它比使用

Answer 1

和

timedelta

对象要干净一些。

这里可以让您入门：

if options['year']:
    start_time = start_time.replace(year=options['year'], month=1, day=1)
    stop_time = stop_time.replace(year=options['year']+1)-timedelta(microseconds=1)

elif options['month']:
    start_time = start_time.replace(month=options['month'], day=1)
    months=options['month']%12+1
    stop_time = stop_time.replace(month=months,day=1)-timedelta(microseconds=1)

else:
    start_time = start_time.replace(day=options['day'])
    stop_time = stop_time.replace(day=options['day'])+timedelta(days=1,microseconds=-1)

dict.get

Answer 2

from datetime import datetime

options = dict(month=5, day=20)
now = datetime.now()
start_time = datetime(year=options.get('year', now.year), 
                      month=options.get('month', 1),
                      day=options.get('day', 1)
                      hour=0,
                      minute=0,
                      second=0)
stop_time =  datetime(year=options.get('year', now.year), 
                      month=options.get('month', now.month),
                      day=options.get('day', now.day),
                      hour=now.hour,
                      minute=now.minute,
                      second=now.second)

    today = datetime.date.today()
    begintime = today.strftime("%Y-%m-%d 00:00:00")
    endtime = today.strftime("%Y-%m-%d 23:59:59")

在这里查看一些答案，但并没有真正找到任何非常优雅的东西，我在标准库周围戳了一下，发现了我当前的解决方案（我非常喜欢）：

from datetime import datetime, date, timedelta

def get_current_timestamp():
    return int(datetime.now().timestamp())

def get_end_today_timestamp():
    # get 23:59:59
    result = datetime.combine(date.today() + timedelta(days=1), datetime.min.time())
    return int(result.timestamp()) - 1

def get_datetime_from_timestamp(timestamp):
    return datetime.fromtimestamp(timestamp)

end_today = get_datetime_from_timestamp(get_end_today_timestamp())

.

。

Answer 3

date = datetime.strftime('<input date str>')

date.replace(hour=0, minute=0, second=0, microsecond=0)  # now we get begin of the day
date += timedelta(days=1, microseconds=-1)  # now end of the day

Answer 4

dateutil

在边缘案例上非常有效。它的天数/月/年正确。如果我有

from datetime import date
from dateutil.relativedelta import relativedelta

now = date.today()
stop_time = now + relativedelta(days=1)
start_time = date(
    # NOTE: I'm not doing dict.get() since in my implementation, these dict
    # keys are guaranteed to exist.
    year = options['year'] or now.year,
    month = options['month'] or now.month,
    day = options['day'] or now.day
)

if options['year']:
    start_time = date(year=options['year'] or now.year, month=1, day=1)
    stop_time = start_time + relativedelta(years=1)

if options['month']:
    start_time = date(
        year = options['year'] or now.year,
        month = options['month'] or now.month,
        day = 1
    )
    stop_time = start_time + relativedelta(months=1)

if options['day']:
    start_time = date(
        year = options['year'] or now.year,
        month = options['month'] or now.month,
        day = options['day'] or now.day,
    )
    stop_time = start_time + relativedelta(days=1)

# ... do stuff with start_time and stop_time here ...

Answer 5

dateutil.relativedata.relativedata

，它将增加一年，并将月份设置为1（效果很好）。

也：在上述实施中，如果用户指定没有可选的日期（年，月或每天） - 我们将退缩到一个不错的默认值（start_time = topay noft，stop_time = timorm），那样我们'默认情况下仅在当天做事。

Answer 6