iOS API函数UIImageWriteToSavedPhotosAlbum
将选择器作为一个参数:
func UIImageWriteToSavedPhotosAlbum(_ image: UIImage,
_ completionTarget: Any?,
_ completionSelector: Selector?,
_ contextInfo: UnsafeMutableRawPointer?)
https://developer.apple.com/documentation/uikit/1619125-uiimagewritetosavedphotosalbum
但是,在swift中,当我调用此函数时,选择器永远不会被识别:
class Base {
func save_image(img:UIImage) {
UIImageWriteToSavedPhotosAlbum(img, self, Selector("image:didFinishSavingWithError:contextInfo:"), nil)
// I also tried this:
// UIImageWriteToSavedPhotosAlbum(img, self, #selector(image(_:didFinishSavingWithError:contextInfo:))
}
@objc func image(_ image: UIImage, didFinishSavingWithError error: Error?, contextInfo: UnsafeRawPointer) {
print("Photo Saved Successfully")
}
}
class Child:Base {
}
// This is how I call the save_image function:
let child = Child()
child.save_image()
正如您所看到的,我尝试从签名和字符串构造选择器,但都不起作用。我总是在运行时遇到这个错误:
'XXX.Child' does not implement methodSignatureForSelector: -- trouble ahead
Unrecognized selector ......
这里发生了什么?我想知道这是因为swift没有看到来自Child类的方法,因为该方法是从Base类继承的?
如何成功通过选择器?
我读过的相关问题:
为您的选择器提供一些指导,以帮助它找到正确的功能:
class Base {
func save_image(img:UIImage) {
UIImageWriteToSavedPhotosAlbum(img, self, #selector(Base.image(_:didFinishSavingWithError:contextInfo:)), nil)
}
@objc func image(_ image: UIImage, didFinishSavingWithError error: Error?, contextInfo: UnsafeRawPointer) {
print("Photo Saved Successfully")
}
}
class Child:Base {
}
// This is how I call the save_image function:
let child = Child()
child.save_image()
methodSignatureForSelector是NSObject的方法。所以,你需要继承NSObject
类。
class Base: NSObject {
...
}