mysql cte递归获取所有兄弟姐妹

Question

我正在尝试根据phone_id 获取给定user_id 的所有兄弟/连接。我的表如下所示（ad_users_id 和 ad_phones_id 是保存有关用户/电话详细信息的特定表的外键）。

id	ad_users_id	ad_phones_id	日期_时间
90	7177	19515
125	1967	202
235	7177	19868
236	7177	19519
237	7177	19516
238	7177	19517
239	7177	20196
245	7177	19585
247	7177	19701
295	7177	19703
342	3915	19868
343	3915	19519
346	3915	19516
426	3915	19517
368	3915	20196
414	3915	19585
403	3915	19701
404	3915	19703
1707	1962	202
2124	1967	25141
2129	9329	25141

基本上我需要获取给定 user_id 的所有直接和间接连接。我设法构建了一个 mysql 查询（递归 CTE），它看起来不太干净，但看起来它也不适用于具有多个 Phone_id 的用户，例如 user_id 7177。

WITH RECURSIVE connections (table_id, user_id, phone_id)
AS (
  SELECT
    CAST(ut.id AS CHAR(200)) AS table_id,
    ut.ad_users_id AS user_id,
    ut.ad_phones_id AS phone_id
  FROM ad_phones_users_taxonomy ut
  WHERE ut.ad_users_id = 7177  -- Starting user
  UNION ALL
  SELECT
    CONCAT(c.table_id, ',', CAST(ut2.id AS CHAR(200))) AS table_id, -- CONCATENARE pentru a evita din bucla id-urile deja trase
    ut2.ad_users_id AS user_id,
    ut2.ad_phones_id AS phone_id
  FROM ad_phones_users_taxonomy ut2
  INNER JOIN connections c ON ut2.ad_phones_id = c.phone_id OR ut2.ad_users_id = c.user_id
    WHERE NOT FIND_IN_SET(ut2.id, c.table_id)
        LIMIT 10
)
SELECT
  table_id, user_id, phone_id
    FROM connections

如有任何建议，我们将不胜感激。

期望检索所有连接（直接和间接），但是对于具有多个phone_id的user_id，几乎“杀死”mysql服务器

--- 稍后编辑--- 这是创建表：

CREATE TABLE `ad_phones_users_taxonomy` (
  `id` int NOT NULL PRIMARY KEY AUTO_INCREMENT,
  `ad_users_id` int DEFAULT NULL,
  `ad_phones_id` int DEFAULT NULL,
  `data_timp` timestamp NULL DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_unicode_ci;

INSERT INTO `ad_phones_users_taxonomy` (`id`, `ad_users_id`, `ad_phones_id`, `date_time`) VALUES
(90, 7177, 19515, '2024-05-08 19:57:41'),
(125, 1967, 202, '2024-05-08 19:58:26'),
(235, 7177, 19868, '2024-05-08 20:02:52'),
(236, 7177, 19519, '2024-05-08 20:02:55'),
(237, 7177, 19516, '2024-05-08 20:02:58'),
(238, 7177, 19517, '2024-05-08 20:03:01'),
(239, 7177, 20196, '2024-05-08 20:03:04'),
(245, 7177, 19585, '2024-05-08 20:03:25'),
(247, 7177, 19701, '2024-05-08 20:03:31'),
(295, 7177, 19703, '2024-05-08 20:05:55'),
(342, 3915, 19868, '2024-05-08 20:08:21'),
(343, 3915, 19519, '2024-05-08 20:08:24'),
(346, 3915, 19516, '2024-05-08 20:08:33'),
(426, 3915, 19517, '2024-05-08 20:12:27'),
(368, 3915, 20196, '2024-05-08 20:09:36'),
(414, 3915, 19585, '2024-05-08 20:11:53'),
(403, 3915, 19701, '2024-05-08 20:11:21'),
(404, 3915, 19703, '2024-05-08 20:11:24'),
(1707, 1962, 202, NULL),
(2124, 1967, 25141, '2024-05-13 19:27:55'),
(2129, 9329, 25141, '2024-05-13 19:45:32');

对于任何 user_id：1962、1967、9329，这将是预期结果：

id	ad_users_id	ad_phones_id	日期_时间
125	1967	202
1707	1962	202
2124	1967	25141
2129	9329	25141

对于任何 user_id 7177 或 3915，预期结果：

id	ad_users_id	ad_phones_id	日期_时间
90	7177	19515
235	7177	19868
236	7177	19519
237	7177	19516
238	7177	19517
239	7177	20196
245	7177	19585
247	7177	19701
295	7177	19703
342	3915	19868
343	3915	19519
346	3915	19516
426	3915	19517
368	3915	20196
414	3915	19585
403	3915	19701
404	3915	19703

Answer 1

CREATE PROCEDURE get_all (in_user_id INT)
WITH RECURSIVE
cte AS (

-- anchor part - select all rows for specified user

  SELECT ad_users_id, ad_phones_id
  FROM ad_phones_users_taxonomy
  WHERE ad_users_id = in_user_id

-- use UNION DISTINCT which will remove duplicates
-- including the users which are processed/collected already

  UNION DISTINCT

-- recursive part - add siblings 
-- join one table copy by the phone then another copy by the user id
-- i.e. get a user with the same phone from t1 
-- then get app phones for this user from t2

  SELECT t2.ad_users_id, t2.ad_phones_id
  FROM cte 
  JOIN ad_phones_users_taxonomy t1 USING (ad_phones_id)
  JOIN ad_phones_users_taxonomy t2 ON t1.ad_users_id = t2.ad_users_id
  )

-- finally retrieve original rows from gathered users

SELECT DISTINCT ad_phones_users_taxonomy.*
FROM ad_phones_users_taxonomy
JOIN cte USING (ad_users_id)
ORDER BY id;

小提琴