SQL Server 选择阶段/序列已丢失或不按顺序的位置

Question

我有一张桌子，里面有

families_id

、

date

、

metric_id

为每个

families_id

插入一条记录，其中将有

date

和

metric_id

1-10。

因此，每个

families_id

应该有 10 条记录，插入的记录带有日期，并且每条记录都应相互关联。所以

metric_id

10 日期应该大于

metric_id

6 日期。

在弥撒中我如何选择他们所在的地方

1. 错过了

   metric_id

2. metric_id

   6 的日期早于

   metric_id

   2
的日期

Answer 1

使用 row_number 为每个系列的 metric_id 和日期分配一个序数，然后它们应该匹配 - 另外 metric_id, 1,2,3,4... 应该与计算出的 row_number() 匹配，也是 1,2,3, 4....

SELECT IQ.* FROM (SELECT families_id, [date], metric_id, 
        ROW_NUMBER() OVER (PARTITION BY families_id ORDER BY [date]) rn_date,
        ROW_NUMBER() OVER (PARTITION BY families_id ORDER BY metricid) rn_metric FROM YourTable) IQ 
    WHERE IQ.rn_date != IQ.rn_metric;

--should detect wrongly ordered metric_ids
SELECT IQ.* FROM (SELECT families_id, [date], metric_id, 
        ROW_NUMBER() OVER (PARTITION BY families_id ORDER BY [date]) rn_date,
        ROW_NUMBER() OVER (PARTITION BY families_id ORDER BY metricid) rn_metric FROM YourTable) IQ 
    WHERE IQ.metric_id != IQ.rn_metric;

另一种可能性 - 检测 metricID，其中日期较早的 id 较高

    SELECT y1.families_id, y1.metric_id FROM yourtable y1
                    WHERE 
                    EXISTS(SELECT 0 FROM yourtable y2 WHERE y1.families_id = y2.families_id 
                                                            AND
                                                            y2.date < y1.date 
                                                            AND
                                                            y2.metricid > y1.metricid)