“列表”对象没有属性“替换”

Question

我正在编写一些代码来将单词加密为波利比乌斯方中的数字，但是我需要输出是彼此相邻的两个数字，例如41 而不是坐标格式 (4, 1)。 Item.replace 尚未消除不必要的字符，因为它返回“list”对象没有属性“replace”。我怎样才能得到我想要的输出？

import numpy as np
polybius_square = np.array([["a","b","c","d","e"],
                  ["f","g","h","i","j"],
                  ["k","l","m","n","o"],
                  ["p","q","r","s","t"],
                  ["u","v","w","x","y"]])
word = str(input("Enter a word"))
wordletters = list(word)
numbers = []
print(wordletters)
print(len(wordletters))
for count in range(0,len(wordletters)):
  solutions = np.argwhere(polybius_square == wordletters[count])
  solutions = solutions.tolist()
*  solutions = [item.replace(3, 10) for item in solutions]*
  print(solutions)
  numbers.append(solutions)
  print(numbers)
print(*numbers, sep=" ")

我尝试了几种方法，但没有一种方法可以让我从列表中的项目中删除任何字符。

Answer 1

当您打印列表时，这只是列表的字符串表示。 对包含数字的列表本身进行操作：

solutions = np.argwhere(polybius_square == wordletters[count])
number = solutions[0][0] * 10 + solutions[0][1]  # It's a 2D ndarray, e.g. [[4 3]]
numbers.append(number)