我的 xslt 2.0 中没有索引的段的分组问题

Question

我尝试完成以下结构：

<?xml version="1.0" encoding="UTF-8"?>
<Response>
    <Responses>
        <index>000010</index>
        <brutto>246.09</brutto>
        <bruttoSingle>246.09</bruttoSingle>
        <netto>7327.14</netto>
        <nettoSingle>244.24</nettoSingle>
        <logisticsFlatRatValue>18.27</<logisticsFlatRatValue>
        <logisticsFlatRatpercentage>0.25</logisticsFlatRatpercentage>
        <Currency>USD</Currency>
    </Responses>
    <Responses/>
    <Responses>
        <index>000020</index>
        <brutto>10.20</brutto>
        <bruttoSingle>10.20</bruttoSingle>
        <netto>2.88</netto>
        <nettoSingle>2.88</nettoSingle
        <logisticsFlatRatValue>18.27</<logisticsFlatRatValue>
        <logisticsFlatRatpercentage>0.25</logisticsFlatRatpercentage>
        <Currency>USD</Currency>
    </Responses>
    <Responses/>
</Response>

这就是我的意见：

<Response>
    <Responses>
        <brutto>
            <indx>000010</indx>
            <value>246.09</value>
            <currency>USD</currency>
        </brutto>
        <bruttoSingle>
            <indx>000010</indx>
            <value>246.09</value>
            <currency>USD</currency>
        </bruttoSingle>
        <logisticsFlatRate>
            <value>18.27</value>
            <percentage>0.25</percentage>
        </logisticsFlatRate>
    </Responses>
    <Responses>
        <netto>
            <indx>000010</indx>
            <value>7327.14</value>
            <currency>USD</currency>
        </netto>
        <nettoSingle>
            <indx>000010</indx>
            <value>244.24</value>
            <currency>USD</currency>
        </nettoSingle>
    </Responses>
    <Responses/>
    <Responses>
        <brutto>
            <indx>000020</indx>
            <value>10.20</value>
            <currency>USD</currency>
        </brutto>
        <bruttoSingle>
            <indx>000020</indx>
            <value>10.20</value>
            <currency>USD</currency>
        </bruttoSingle>
    </Responses>
    <Responses>
        <netto>
            <indx>000020</indx>
            <value>2.88</value>
            <currency>USD</currency>
        </netto>
        <nettoSingle>
            <indx>000020</indx>
            <value>2.88</value>
            <currency>USD</currency>
        </nettoSingle>
        <logisticsFlatRate>
            <value>15.27</value>
            <percentage>0.45</percentage>
        </logisticsFlatRate>
    </Responses>
    <Responses/>
</Response>

到目前为止我的xslt：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="/">
        <xsl:for-each-group select="//Responses/*[index]" group-by="index">
            <group>
                <index><xsl:value-of select="current-grouping-key()"/></index>
                <items>
                    <xsl:for-each select="current-group()">
                        <xsl:element name="{name()}">
                            <xsl:value-of select="value"/>
                        </xsl:element>
                    </xsl:for-each>
                    <xsl:for-each select="/Response/Responses/logisticsFlatRate">
                        <xsl:copy-of select="."/>
                    </xsl:for-each>
                </items>
            </group>
        </xsl:for-each-group>
    </xsl:template>
</xsl:stylesheet>

我知道logistic Flat的这一部分是错误的，我尝试使用上面的分组，但由于logisticFlatRate段中没有索引，所以它不起作用。

我在货币和物流方面苦苦挣扎。我的目标是拥有一个像上面的例子一样的扁平结构

Answer 1

此代码：

<xsl:for-each select="/Response/Responses/logisticsFlatRate">
    <xsl:copy-of select="."/>
</xsl:for-each>

显然是错误的，因为前导“/”从文档的根目录中进行选择，并且这里没有任何内容表明您要复制 which

logisticsFlatRate

。就此而言，您还没有告诉我们足够多的问题，让我们无法回答这个问题。但鉴于您的示例数据，您也许可以使用

<xsl:apply-templates select="current-group()/following-sibling::logisticsFlatRate"/>

加上适当的模板规则，将

logisticsFlatRate

转换为您在输出中实际想要的两个元素。