我是Web编程的新手,会在下面的代码中询问建议。
我在数据库类中有代码。有。如您所见,mysqli与数据库建立了连接。并且此代码有效。
function __construct() {
$this->conn = $this->connectDB();
}
function connectDB() {
$conn = mysqli_connect($this->host,$this->user,$this->password,$this->database);
return $conn;
}
function runBaseQuery($query) {
$result = mysqli_query($this->conn,$query);
while($row=mysqli_fetch_assoc($result)) {
$resultset[] = $row;
}
if(!empty($resultset))
return $resultset;
}
function runQuery($query, $param_type, $param_value_array) {
$sql = $this->conn->prepare($query);
$this->bindQueryParams($sql, $param_type, $param_value_array);
$sql->execute();
$result = $sql->get_result();
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$resultset[] = $row;
}
}
if(!empty($resultset)) {
return $resultset;
}
}
function bindQueryParams($sql, $param_type, $param_value_array) {
$param_value_reference[] = & $param_type;
for($i=0; $i<count($param_value_array); $i++) {
$param_value_reference[] = & $param_value_array[$i];
}
call_user_func_array(array(
$sql,
'bind_param'
), $param_value_reference);
}
function insert($query, $param_type, $param_value_array) {
$sql = $this->conn->prepare($query);
$this->bindQueryParams($sql, $param_type, $param_value_array);
$sql->execute();
}
function update($query, $param_type, $param_value_array) {
$sql = $this->conn->prepare($query);
$this->bindQueryParams($sql, $param_type, $param_value_array);
$sql->execute();
}
我必须在PDO中编写此类。我已经做到了,但是出了点问题。我尝试连接我的数据库并收到错误
致命错误:未捕获的TypeError:PDO :: __ construct()需要参数4
class DB {
private $host = "";
private $user = "";
private $password = "";
private $database = "";
private $pdo;
function __construct() {
$this->pdo = $this->connectDB();
}
function connectDB() {
try
{
$pdo = new PDO($this->host,$this->user,$this->password,$this->database);
}
catch (PDOException $e) {
print "Error!: " . $e->getMessage();
}
die();
}
function runBaseQuery($query)
{
$result = $pdo->query($query);
while ($row = $pdo->fetch(PDO::FETCH_ASSOC)) {
$resultset[] = $row;
}
if (!empty($resultset))
return $resultset;
}
function runQuery($query, $param_type, $param_value_array) {
$sql = $pdo->prepare($query);
$pdo->execute($sql, $param_type, $param_value_array);
$result = $pdo->fetchAll(PDO::FETCH_ASSOC);
if ($result->num_rows > 0) {
while ($row = $pdo->fetchAll(PDO::FETCH_ASSOC)) {
$resultset[] = $row;
}
}
if(!empty($resultset)) {
return $resultset;
}
}
function bindQueryParams($sql, $param_type, $param_value_array) {
$param_value_reference[] = & $param_type;
for($i=0; $i<count($param_value_array); $i++) {
$param_value_reference[] = & $param_value_array[$i];
}
call_user_func_array(array(
$sql,
'bind_param'
), $param_value_reference);
}
function insert($query, $param_type, $param_value_array) {
$sql = $pdo->prepare($query);
$pdo->execute($sql, $param_type, $param_value_array);
}
function update($query, $param_type, $param_value_array) {
$sql = $pdo->prepare($query);
$pdo->execute($sql, $param_type, $param_value_array);
}
}
但是我的新代码不起作用。问题出在哪里?
PDO连接没有第四个参数作为数据库名称。数据库名称与主机名一起传递。因此更改:
$pdo = new PDO($this->host,$this->user,$this->password,$this->database);
到:
$pdo = new PDO($this->host . ';dbname=' . $this->database, $this->user, $this->password);
有关更多信息,请参见https://www.php.net/manual/en/pdo.connections.php
此外,还不清楚$this->host
包含什么,但对于PDO,如果这只是一个主机路径,您还需要传递您正在使用的驱动程序,那么您甚至可能需要添加]]
mysql:host=
到此开始。对于
mysqli
,这不是必需的,因为唯一的RDBMSmysqli
支持的是mysql
。
因此可能是完整的答案:
$pdo = new PDO('mysql:host=' . $this->host . ';dbname=' . $this->database, $this->user, $this->password);
您的新班级有多个问题。您所要解决的问题可以通过了解如何与PDO正确连接以及DSN是什么来解决。为此,我必须向您推荐这篇很棒的文章https://phpdelusions.net/pdo#dsn