从 Nuxt createError 响应中删除堆栈字段

Question

我制作了服务器 API 来验证 Nuxt 上的一些数据，如下所示：

export default defineEventHandler(async (event) => {
  const body = await readBody(event);

  const result = schema.safeParse(body);

  if (result.success === false) {
    const error = result.error;

    const customError = createError({
      statusCode: 412,
      statusMessage: `${error.errors[0].path} ${error.errors[0].message}`,
    });
    throw customError;
  }

  return { ok: true };
});

因此，当我输入错误时，createError 函数会被调用，并且我会得到如下返回：

{
    "url": "/api/car/listings",
    "statusCode": 412,
    "statusMessage": "make Required",
    "message": "make Required",
    "stack": "<pre><span class=\"stack internal\">at createError (/H:/nuxt/cartrader/node_modules/h3/dist/index.mjs:48:15)</span>\n<span class=\"stack\">at /H:/nuxt/cartrader/.nuxt/dev/index.mjs:794:25</span>\n<span class=\"stack internal\">at process.processTicksAndRejections (node:internal/process/task_queues:95:5)</span>\n<span class=\"stack internal\">at async Object.handler (/H:/nuxt/cartrader/node_modules/h3/dist/index.mjs:723:19)</span>\n<span class=\"stack internal\">at async Server.toNodeHandle (/H:/nuxt/cartrader/node_modules/h3/dist/index.mjs:798:7)</span></pre>"
}

问题是如何删除错误响应中的堆栈字段，因为在 JSON 响应中使用该堆栈字段有点烦人，尤其是如果您想与其他人共享该 api 时？我尝试像这样删除它：

const customError = createError({
      statusCode: 412,
      statusMessage: `${error.errors[0].path} ${error.errors[0].message}`,
    });
    delete customError.stack;
    throw customError;

但它只删除堆栈字段内的内容，并且它本身的字段仍然存在

{
    "url": "/api/car/listings",
    "statusCode": 412,
    "statusMessage": "make Required",
    "message": "make Required",
    "stack": "<pre></pre>"
}

Answer 1

对此做了一些研究。显然它只包含堆栈字段如果服务器处于开发模式。所以这不会添加到生产中。

如果它确实在开发中困扰您，最干净的“修复”（本质上与

delete

相同），您可以这样做：

throw createError({
  statusCode: 412,
  statusMessage: `${error.errors[0].path} ${error.errors[0].message}`,
  stack: undefined,
});