我在while循环和switch语句中遇到语法错误，并对为什么[重复]感到困惑

Question

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• How to check if an integer is in a given range? 18个答案

我在while循环和switch语句中遇到语法错误，这是我在使用这种语法之前没有得过的。

我尝试过为循环和switch语句使用各种不同的格式。它仍然提供语法错误错误消息显示“令牌上的语法错误，错位的构造”和“令牌上的语法错误”案例“，断言预期”。

   Scanner input = new Scanner(System.in);
   System.out.println("Please enter a number between 1 and 14. I will 
then tell you the playing card assosiated with it.");
   int x = intput.nextInt();
   while(1<x<=14){
     Switch(x){
       case 1:
         System.out.println("Your card is an Ace.");
         break;
       case 2:
         System.out.println("Your card is a two.");
         break;
       case 3:
         System.out.println("Your card is a three.");
         break;
       case 4:
         System.out.println("Your card is a four.");
         break;
       case 5:
         System.out.println("Your card is a five.");
         break;
       case 6:
         System.out.println("Your card is a six.");
         break;
       case 7:
         System.out.println("Your card is a seven.");
         break;
       case 8:
         System.out.println("Your card is an eight.");
         break;
       case 9:
         System.out.println("Your card is a nine.");
         break;
       case 10:
         System.out.println("Your card is a ten.");
         break;
       case 11:
         System.out.println("Your card is an Ace.");
         break;
       case 12:
         System.out.println("Your card is a Jack.");
         break;
       case 13:
         System.out.println("Your card is a Queen.");
         break;
       case 14:
         System.out.println("Your card is a King.");
         break;
     }
     System.out.println("Please enter a number between 1 and 14. I will 
then tell you the playing card assosiated with it.");
     x = input.nextInt();
   }
  }
}

Answer 1

java中没有这样的东西：while(1<x<=14)。你一次只能比较两个数字，所以你必须写：while(1 < x && x <= 14)。