c＃托盘应用程序中的ContextMenuStrip在展开的图标窗口中没有正确反应

Question

我创建了一个带有图标的托盘应用程序，可以在Icon Click上打开ContextMenuStrip。我有三个可以单击的ToolStripMenuItem。

只要图标直接可见，托盘应用程序就可以正常工作。但是，如果我必须点击雪佛龙来展开不可见的托盘图标，我遇到了一个问题。我可以点击项目打开菜单。如果我单击其中一个ToolStripMenuItems，则“Tray-Menu”会进入“Expanded Tray Icons”的背景，并且无法再单击。我怎么能阻止这个？似乎背景是捕获点击而不是开放形式。

这是菜单的代码。

class Menu
{
    private static ContextMenuStrip contextMenuStrip;
    private static NotifyIcon notifyIcon1 = new NotifyIcon();
    public Menu()  
    {
        notifyIcon1.Icon = new Icon("icon.ico");
        notifyIcon1.Text = "icon";
        contextMenuStrip = new ContextMenuStrip();
        ToolStripItem stripItem0 = new ToolStripMenuItem("open");
        contextMenuStrip.Items.AddRange(new ToolStripItem[] { stripItem0 });
        ToolStripItem stripItem1 = new ToolStripMenuItem("stop");
        stripItem1.Click += new EventHandler(ToggleTracking);
        contextMenuStrip.Items.AddRange(new ToolStripItem[] { stripItem1 });
        ToolStripItem line = new ToolStripSeparator();
        contextMenuStrip.Items.AddRange(new ToolStripItem[] { line });
        ToolStripItem stripItem2 = new ToolStripMenuItem("close");
        stripItem2.Click += new EventHandler(Close);
        contextMenuStrip.Items.AddRange(new ToolStripItem[] { stripItem2 });

        notifyIcon1.ContextMenuStrip = contextMenuStrip;
        //notifyIcon1.ContextMenu = contextMenu1;
        notifyIcon1.Click += new EventHandler(IconClick);
        notifyIcon1.Visible = true;
    }

    private void ToggleTracking(object Sender, EventArgs e)
    {
        ToolStripMenuItem stripItem1 = (ToolStripMenuItem)contextMenuStrip.Items[1];
        if (stripItem1.Text == "stop")
        {
            stripItem1.Text = "restart";
            Batch.StopTimer();
        }
        else
        {
            stripItem1.Text = "stop";
            Batch.RestartTimer();
        }
    }

    private void Close(object Sender, EventArgs e)
    {
        Application.Exit();
    }
    private void IconClick(object Sender, EventArgs e)
    {
        Control strip = Sender as Control;
        if (contextMenuStrip.Visible)
        {
            contextMenuStrip.Hide();
        }
        else
        {
            contextMenuStrip.Show(Cursor.Position);
        }
    }
}

Answer 1

我不得不像这样使用BringToFront方法。

{
    contextMenuStrip.Show(Cursor.Position);
    contextMenuStrip.BringToFront();
}

https://msdn.microsoft.com/de-de/library/system.windows.forms.control.bringtofront(v=vs.110).aspx