如何使用 NiFi (1.25) JSLTTransformJSON 处理器从数组中获取特定字段作为单个条目

Question

我有 JSON 输入，我想从中将数组的相同子元素提取到一个字段中。尝试弄清楚如何使用 NiFi JSLTTransformJSON 处理器构建 JSLT。

输入：

{
  "name": "John Smith",
  "ID": "123123123",
  "address": [
    {
      "location": "123 Main, Citty, ST",
      "info": {
        "type": "single family",
        "own": "yes"
      }
    },
    {
      "location": "123 Lane, Wonderland, ST",
      "info": {
        "type": "apartment",
        "own": "yes"
      }
    },
    {
      "location": "123 Street, Place, ST",
      "info": {
        "type": "condo",
        "own": "no"
      }
    }
  ]
}

所需输出：

{
  "name": "John Smith",
  "ID": "123123123",
  "residence_type": "single family, apartment, condo"
}

所需输出，其中

info.own == "yes"

:

{
  "name": "John Smith",
  "ID": "123123123",
  "residence_type": "123 Main, Citty, ST; 123 Lane, Wonderland, ST"
}

我不知道可能有多少个地址。

Answer 1

对于第一个所需的输出：

{

  
  "residence_type":join([for (.address) .info.type],", "),
  "address":null,
  *:.

}

对于第二个所需的输出：

{

  
  "residence_type":join([for (.address) .location if(.info.own=="yes")],", "),
  "address":null,
  *:.

}

如果您尝试根据 info.own 值组合两者：

{

  
  "residence_type":join([for (.address) .location if(.info.own=="yes")]+[for (.address) .info.type if(.info.own!="yes")] ,"; "),
  "address":null,
  *:.

}

希望有帮助。