单个查询中两列的总计和总和

Question

我的要求与此问题和答案类似PostgreSQL - 计算 COUNT() 的 SUM() 但需要另一列的总计

我有类似的东西

create table Item
(
     ItemID          INTEGER               not null,
     ItemCode        NCHAR(10)             not null,
     ItemName        NCHAR(10)             not null,
     constraint PK_ITEM primary key (ItemID)
);

create table Store
(
    StoreID             INTEGER             not null,
    StoreName           NCHAR(20)           not null,
    ItemID              INTEGER             not null,
    Location            NCHAR(20)           not null,
    constraint PK_STORE primary key (StoreID),
    foreign key (ItemID) references Item(ItemID)
);

insert into Item (ItemID,ItemCode,ItemName) Values (1,'abc','abc');
insert into Item (ItemID,ItemCode,ItemName) Values (2,'def','def');
insert into Item (ItemID,ItemCode,ItemName) Values (3,'ghi','ghi');

insert into Store (StoreID,StoreName,ItemID,Location) Values (1,'B1',1,'L1');
insert into Store (StoreID,StoreName,ItemID,Location) Values (2,'B2',2,'L2');
insert into Store (StoreID,StoreName,ItemID,Location) Values (3,'B3',1,'L3');
insert into Store (StoreID,StoreName,ItemID,Location) Values (4,'B4',2,'L1');
insert into Store (StoreID,StoreName,ItemID,Location) Values (5,'B5',3,'L2');
insert into Store (StoreID,StoreName,ItemID,Location) Values (6,'B6',2,'L3');
insert into Store (StoreID,StoreName,ItemID,Location) Values (7,'B7',3,'L1');
insert into Store (StoreID,StoreName,ItemID,Location) Values (8,'B8',1,'L3');
insert into Store (StoreID,StoreName,ItemID,Location) Values (9,'B9',2,'L1');

这个我试过了

select count(I.ItemID), S.ItemID, I.ItemCode,  count(S.Location),S.Location
from Store S, Item I where S.ItemId=I.ItemID 
group by S.ItemID, I.ItemCode, S.Location ;

结果是这样的

数	项目中	商品代码	数	地点
2	1	abc	2	L3
1	1	abc	1	L1
1	2	定义	1	L3
2	2	定义	2	L1
1	2	定义	1	L2
1	3	吉	1	L2
1	3	吉	1	L1

我想要这样的东西，其中显示 itemId 的总数

数	项目中	商品代码	数	地点
3	1	abc	2	L3
3	1	abc	1	L1
4	2	定义	1	L3
4	2	定义	2	L1
4	2	定义	1	L2
2	3	吉	1	L2
2	3	吉	1	L1

或者最好是这样

项目中	商品代码	数	地点
1	abc	2	L3
1	abc	1	L1
1	总计	3	<-------
2	定义	1	L3
2	定义	2	L1
2	定义	1	L2
2	总计	4	<-------
3	吉	1	L2
3	吉	1	L1
3	总计	2	<-------

如何实现这一目标？

Answer 1

您可以在单个查询中进行单独的选择，并使用

join

或

union

组合结果。对于第一个预期输出，您可以像下面这样查询

select sq1.count, sq1.ItemID, sq2.ItemCode, sq2.count, sq2.Location from (
  select S1.ItemID, count(*)  as count
  from Store S1
  group by S1.ItemID
) sq1
inner join (
  select S2.ItemID, I.ItemCode, Count(*), S2.Location from Store S2 
  inner join Item I
  on S2.ItemId = I.ItemId
  group by S2.ItemID, I.ItemCode, S2.Location
) sq2
on sq1.ItemID = sq2.ItemID
order by sq2.ItemID, sq2.ItemCode;

对于第二个结果，您可以使用此查询

select * from (
  select S.ItemID, I.ItemCode, Count(*), S.Location from Store S 
  inner join Item I
  on S.ItemId = I.ItemId
  group by S.ItemID, I.ItemCode, S.Location
  union
  select  S2.ItemID, 'Total'  as itemcode, Count(*), null
  from Store S2
  group by S2.ItemID
) sq
order by sq.ItemID, sq.ItemCode;