在这里，我有excel到pdf转换脚本如何更改为重置api。
import os
import comtypes.client
SOURCE_DIR = 'D:/projects/python'
TARGET_DIR = 'D:/projects/python'
app = comtypes.client.CreateObject('Excel.Application')
app.Visible = False
infile = os.path.join(os.path.abspath(SOURCE_DIR), 'ratesheet.xlsx')
outfile = os.path.join(os.path.abspath(TARGET_DIR), 'ratesheet.pdf')
doc = app.Workbooks.Open(infile)
doc.ExportAsFixedFormat(0, outfile, 1, 0)
doc.Close()
app.Quit()
您可以使用Python的Flask轻量级Rest Framework来使您的程序可以访问REST调用。查看本教程：http://flask.pocoo.org/docs/1.0/tutorial/
在那里，您可以简单地以POST格式输入文件，一旦文件被转换，就会向最终用户发送可下载的链接。你必须调整我和朋友写的代码用于类似的目的：
import os
from flask import Flask, request, redirect, url_for
from werkzeug import secure_filename
PROJECT_HOME = os.path.dirname(os.path.realpath(__file__))
UPLOAD_FOLDER = '{}/uploads/'.format(PROJECT_HOME)
ALLOWED_EXTENSIONS = set(['txt','pdf', 'vcf'])
app = Flask(__name__)
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
def allowed_file(filename):
return '.' in filename and \
filename.rsplit('.', 1)[1] in ALLOWED_EXTENSIONS
@app.route("/", methods=['GET', 'POST'])
def index():
if request.method == 'POST':
file = request.files['file']
if file and allowed_file(file.filename):
filename = secure_filename(file.filename)
file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
_path = os.path.abspath("<FILE PATH>")
uf = str(uuid.uuid4())
# DO YOUR AMAZING STUFF HERE
return redirect(url_for('index'))
return """
<!doctype html>
<title>Upload new File</title>
<h1>Upload new File</h1>
<form action="" method=post enctype=multipart/form-data>
<p><input type=file name=file>
<input type=submit value=Upload>
</form>
<p>%s</p>
""" % "<br>".join(os.listdir(app.config['UPLOAD_FOLDER'],))
if __name__ == "__main__":
app.run(host='0.0.0.0', port=5001, debug=True)