Django 文件上传循环

Question

我最好如何循环这样的表单（表单中还有其他代码，但这是图像上传的示例）

<form action="{% url "upload" %}" method="post" enctype="multipart/form-data">
  {% csrf_token %}
  <input type="file" name="image_file">
  <input type="file" name="image_file2">
  <input type="file" name="image_file3">
  <input type="file" name="image_file4">
  <input type="file" name="image_file5">
  <input type="submit" value="submit" />
</form>

适用于单个文件上传，但需要多文件上传：

def image_upload(request):
    if request.method == "POST" and request.FILES["image_file"]:
        image_file = request.FILES["image_file"]
        fs = FileSystemStorage()
        filename = fs.save(image_file.name, image_file)
        image_url = fs.url(filename)
        print(image_url)
        return render(request, "upload.html", {
            "image_url": image_url
        })
    return render(request, "upload.html")

只是不知道如何循环它，以便图像与文件名一起存储在数据库的 var 中（稍后）也只是一个想法，可能并不总是上传所有五个文件，可能是三个或没有

Answer 1

如果我理解正确的话，您只是想循环遍历 5 个字段（image_file 到 image_file5），并保存每个字段（如果上传了文件）？

如果是这样，那几乎非常简单，因为您可以使用计算结果或变量，而不仅仅是硬编码字符串。 唯一（轻微）的问题是第一个字段没有用“1”命名，但是可以使用 if 条件轻松处理。 为了便于理解，我将保持简单；如果我要创建此功能，我可能会采取完全不同的方法。 无论如何，使用 for 循环，循环范围 1 到 5（range 函数返回一个从第一个参数到第二个参数减 1 的迭代器，这就是为什么我们使用 range(1, 6) 而不是 Range(1 , 5))，并使用当前迭代器编号构造当前文件字段的名称。 像这样：

def image_upload(request):
    if request.method == "POST":
        image_urls = dict()
        for i in range(1, 6):
            file_key = f"image_file{i}" if i > 1 else "image_file"  # If you're using Python 2, f-strings won't work, but you could do either "image_file{}".format(i) or "image_file%d" % (i, )
            image_file = request.FILES.get(file_key, None)  # This format retrieves the file if the named file exists, otherwise it will result in None (because I specified None as the default falue in the second argument).  This is safer against potential errors, if the field doesn't exist or has no file associated
            if image_file:  # Since we stored the image file, or None if missing, in the variable called image_file, we'll just check that; if it has a non-Non value, this line resolves to True
                fs = FileSystemStorage()
                filename = fs.save(image_file.name, image_file)
                image_urls[file_key] = fs.url(filename)
            else:
                image_urls[file_key] = ""  # Or maybe you'd want None here

        #
        # Here I am rendering the template after saving all 5 files, and including the URLs for all 5.  But I don't know what the intent 
        # is here, so you might need to write something else.  In the context for this render call, I am unpoacking the dictionary key/value
        # pairs recorded in the loop, into keyword variable pairs.
        return render(request, "upload.html", {
            **image_urls,
        })
        return render(request, "upload.html")                    

我知道这个回复晚了两年，但我在寻找东西时遇到了这个，我不敢相信它还没有解决。