如何在 Selenium 中提取和保存链接

Question

作为 Selenium 的新手，我的第一次尝试是保存页面上的所有链接。我的代码来自一个我无法工作的示例。 我做错了什么？

这是我的代码：

import selenium
from selenium import webdriver
from selenium.webdriver.chrome.service import Service
from webdriver_manager.chrome import ChromeDriverManager
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC


url = "https://www.python.org"

driver = webdriver.Chrome()
driver.get(url)
driver.minimize_window()

links = WebDriverWait(driver, 10).until(EC.visibility_of_all_elements_located((By. LINK_TEXT, "a")))


for link in links:
    href = link.get_attribute("href")
    if href is not None:
        print(href)

driver.quit()

另外，如何保存链接并能够在需要时单击它们。

这是我收到的错误消息。

Traceback (most recent call last):
  File "/media/joe-2/Ubuntu-Storage1/Exuma-Snoops/RGD-code/link-test.py", line 21, in <module>
    links = WebDriverWait(driver, 10).until(EC.visibility_of_all_elements_located((By. LINK_TEXT, "a")))
  File "/home/joe-2/.local/lib/python3.10/site-packages/selenium/webdriver/support/wait.py", line 105, in until
    raise TimeoutException(message, screen, stacktrace)
selenium.common.exceptions.TimeoutException: Message: 

我的操作系统是Ubuntu 22.04

Answer 1

links = WebDriverWait(driver, 10).until(EC.visibility_of_all_elements_located((By. LINK_TEXT, "a")))

将上面的行更改如下：

links = WebDriverWait(driver, 10).until(EC.presence_of_all_elements_located((By.XPATH, "//a")))