如何在 C++ 中调用 DLL void 函数

Question

我正在从 DLL 调用一个 void 函数，其中参数通过引用传递。 每当我调用它时，函数都会执行，但参数变量不受影响。 谁能告诉我我做错了什么？

#include <iostream>
#include <windows.h>

using namespace std;

class ck
{
    public:
        unsigned short cm, mb, nm;
};

int main()
{
ck temp;
typedef void(WINAPI *func)(ck);
func ini_v;
HINSTANCE LibDLL = NULL;
LibDLL = LoadLibrary("Ini_vector.dll");
if (LibDLL != NULL)
{
    ini_v = (func)GetProcAddress(LibDLL, "ini_vector");
    ini_v(temp);
    cout << "nm = " << temp.nm << "     cm = " << temp.cm<<"     bm = "<< temp.mb << endl << endl << "END";
    FreeLibrary(LibDLL);
    LibDLL = NULL;
}
else
    cout << "ERROR." << endl;
cin.get();
return 0;
}

//This is the function included in the DLL
extern "C" __declspec(dllexport)
void ini_vector(ck& C)
{
C.nm = 11;
C.cm = 39;
C.mb = 23;
}