DataTables警告:table = userTable-无效的JSON响应?

问题描述 投票:5回答:2

我使用jQuery DataTables并收到此警告消息:

[DataTables警告:table = userTable-无效的JSON响应

一个servlet从MySQL获取用户,我想在jQuery数据表中显示该用户,但是Ajax无法解析JSON或JSON在servlet中生成错误?

Servlet:

    List<UserDTO> users = this.service.getAllUser();
                Gson gson = new Gson();
                request.setAttribute("users", gson.toJson(users));
                request.getRequestDispatcher("listAllUser.jsp").forward(request, response);

JSP:

    <%@ page language="java" contentType="text/html; charset=ISO-8859-1"
        pageEncoding="ISO-8859-1"%>
    <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
    <html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
    <title>Registered Users</title>
    <script src="http://code.jquery.com/jquery-1.10.2.js"></script>
    <script src="http://code.jquery.com/ui/1.11.4/jquery-ui.js"></script>
    <script
        src="https://cdn.datatables.net/1.10.9/js/jquery.dataTables.min.js"></script>
    <link rel="stylesheet"
        href="http://cdn.datatables.net/1.10.9/css/jquery.dataTables.min.css" />
    <link rel="stylesheet"
        href="http://code.jquery.com/ui/1.11.4/themes/flick/jquery-ui.css">
    <script>
        $(document).ready(function() {
            $('#userTable').dataTable({
                "processing" : true,
                "serverSide" : true,
                "ajax" : {
                    "url" : "ListAllUserServlet",
                    "type" : "POST"
                },
                "columns" : [ {
                    "data" : "id"
                }, {
                    "data" : "userName"
                }, {
                    "data" : "firstName"
                }, {
                    "data" : "lastName"
                }, {
                    "data" : "email"
                }, {
                    "data" : "phone"
                }, {
                    "data" : "location"
                }, {
                    "data" : "password"
                }, {
                    "data" : "gender"
                }, {
                    "data" : "birthday"
                } ]
            });
        });
    </script>

    </head>
    <body>
        <table id="userTable" class="display">
            <thead>
                <tr>
                    <th colspan="10" id="userList">Users</th>
                </tr>
                <tr>
                    <th>User id</th>
                    <th>User name</th>
                    <th>First Name</th>
                    <th>Last Name</th>
                    <th>Email</th>
                    <th>Phone</th>
                    <th>Location</th>
                    <th>Password</th>
                    <th>Gender</th>
                    <th>Birth date</th>
                </tr>
            </thead>

            <tfoot>
                <tr>
                    <td colspan="10"><a href="index.jsp" id="toIndex">Back</a></td>
                </tr>
            </tfoot>
        </table>

    </body>
    </html>

由Servlet生成的JSON:

[
    {
        "id": 1,
        "userName": "userName1",
        "firstName": "firstName1",
        "lastName": "lastName1",
        "email": "[email protected]",
        "phone": "36202080085",
        "location": "location1",
        "password": "password1",
        "gender": "m",
        "birthday": "1-02-2015"
    }
]
jquery jsp servlets datatables gson
2个回答
8
投票

    您已通过"serverSide": true启用了服务器端处理模式,但是您的数据被格式化为客户端处理模式。删除"serverSide": true以使用客户端处理模式。
  • 您需要使用下面显示的dataSrc: ""灰以匹配JSON数据格式,有关更多信息,请参见dataSrc

  • dataSrc

0
投票
"ajax" : { "url" : "ListAllUserServlet", "type" : "POST", "dataSrc": "" },
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