如何从 python 中的 random.randint 获取另一个数字？

Question

我正在尝试制作一个随机数猜测游戏，如果用户得到它，我会问他们是否想再玩一次。问题是，如果他们同意，随机数将与上次相同。我是 python 新手，如果你能帮助我，我真的很感激。另外，如果有什么可以改进的地方，请告诉我！

这是我的代码：

while True:
    i = 1
    import random
    number = random.randint(1, 1000)
       
    while 1 != 0:
        player_guess = input("Choose a number from 1-1000 ")
        if int(player_guess) == number:
            print("You got it!")
            i-1
            x = input("do you want to play again? (y/n) ")
            if x == "y":
                import random
                continue
            if x == "n":
                exit()
        elif int(player_guess) >= number:
            print("Too high!")
        elif int(player_guess) <= number:
            print("Too low!")

Answer 1

你必须存在内循环

while 1 != 0

- 它需要

break

而不是

continue

。

命令

continue

转到当前

while 1 != 0

的开头，但不会退出。

import random  # PEP8: all imports at the beginning of code

while True:
    number = random.randint(1, 1000)
       
    while True:
        player_guess = input("Choose a number from 1-1000 ")
        player_guess = int(player_guess)
        
        if player_guess == number:
            print("You got it!")
            
            x = input("do you want to play again? (y/n) ")
            x = x.lower() 
            
            if x == "y":
                break  # exit current loop
            elif x == "n":
                exit()
                
        elif player_guess >= number:
            print("Too high!")
        elif player_guess <= number:
            print("Too low!")

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PEP 8 -- Python 代码风格指南