错误 java.lang.NumberFormatException 如果我尝试将 2 个单词插入单个字符串 (Java)

Question

错误 java.lang.NumberFormatException 如果我尝试将 2 个单词插入单个字符串（Java）!!

显示的错误是：

Enter item Chicken rice 输入金额（第纳尔）

线程“main”中的异常 java.lang.NumberFormatException: For input 字符串：“大米”在 java.base/java.lang.NumberFormatException.forInputString(NumberFormatException.java:67) 在 java.base/java.lang.Integer.parseInt(Integer.java:668) 处 java.base/java.lang.Integer.valueOf(Integer.java:999) 在 Sampleproject1/t4.Main.main(Main.java:65)

import java.util.*;

class Expense implements Comparable<Expense>{
    
    String expenseCategory;
    Integer amount;
    
    
    public String getExpenseCategory() {
        return expenseCategory;
    }
    public void setExpenseCategory(String expenseCategory) {
        this.expenseCategory = expenseCategory;
    }
    public Integer getAmount() {
        return amount;
    }
    public void setAmount(Integer amount) {
        this.amount = amount;
    }   
    
    public Expense(String expC , Integer amount) {
        this.expenseCategory=expC;
        this.amount = amount;
    }
        
    public String toString() {
        return expenseCategory+ " " +amount;
    }
        
    public int compareTo(Expense e) {
        if(amount>e.amount){    
            return 1;    
        }else if(amount<e.amount){    
            return -1;    
        }else{    
        return 0;    
        } 
    }
}

public class Main {
    
    public static void main(String[] args) {
        
        Scanner sc = new Scanner(System.in);
        
        TreeSet<Expense> set1 = new TreeSet<Expense>();

        int tamount=0;
        
        while(true) {
            System.out.println("Enter item");
            String expC = sc.next();
            System.out.println("Enter amount(Dinar)");
            String amt = sc.next();
            tamount = tamount + Integer.valueOf(amt);
            set1.add(new Expense(expC,Integer.valueOf(amt)));
            System.out.println("Do you want to continue(yes/no):");
            String cond = sc.next();
            if(cond.equals("no")) {
                break;
            }else {continue;}
        }
        System.out.println("Total dinar required is:");
        System.out.println("Category    Amount(Dinar)");
        Iterator x = set1.descendingIterator();
            
        while(x.hasNext()) {
            System.out.println(x.next());
        }
                
        System.out.println("Total amount needed in Dinar:"+ tamount);
        System.out.println("Total amount needed in Rupees:"+ tamount*18.565);   
    }       
}

Output should be like :
Enter item
Fried Rice
Enter amount(Dinar)
20
Do you want to continue(yes/no):
yes
Enter item
Chicken Lollipop
Enter amount(Dinar)
25
Do you want to continue(yes/no):
yes
Enter item
Coffee
Enter amount(Dinar)
5
Do you want to continue(yes/no):
no
Total dinar required is:
Item           Amount(Dinar)  
Chicken Lollipop25             
Fried Rice     20             
Coffee         5              
Total amount needed in Dinar: 50
Total amount needed in Rupees: 928.25

如果我使用 nextLine();一些输入被跳过!!

Answer 1

从您的示例中可以清楚地看出，您打算将“输入”键作为输入之间的分隔符。但是，开箱即用，扫描仪将 any whitespace 视为分隔符。简单地告诉它你只想要换行符。

new Scanner(System.in)

之后立即：

scanner.useDelimiter("\\R");

\\R

是“任何换行变体”的正则表达式。

Answer 2

通过为所有语句添加 nextLine() 来修复它