SQL：HAVING条件SUM

Question

我已经构建了一个查询，将公司的销售统计数据与其他公司进行比较。

简化，就像：

SELECT SUM(CASE WHEN company=foobar THEN sales ELSE 0) as sales_foobar,
SUM(sales) as sales_total, country, year, product FROM sales_table
GROUP BY country, year, product HAVING (the above sum again) > 0

合规性规则要求只显示公司有任何销售的行，而我的代码将丢弃foobar没有销售的行，而且由于订单和退款等于销售额为0，它们也会丢弃。

现在，我怎样才能获得公司有销售数据的行？

Answer 1

您可以在HAVING子句中计算与公司匹配的行数：

SELECT SUM(CASE WHEN company = foobar THEN sales ELSE 0 END) as sales_foobar,
       SUM(sales) as sales_total, country, year, product
FROM sales_table
GROUP BY country, year, product
HAVING SUM( company = foobar ) > 0;  -- there is at least one record for the company

Answer 2

你应该使用Where：

   SELECT SUM(CASE WHEN company=foobar THEN sales ELSE 0) as sales_foobar,
    SUM(sales) as sales_total, country, year, product 
    FROM sales_table
    Where sales > 0
    GROUP BY country, year, product HAVING (the above sum again) > 0

Answer 3

根据你的问题，假设公司='foobar;您几乎只在代码中完成了答案。因此，如果您需要除此之外的任何其他特定标准，请告知我们。我会编辑答案。

SELECT 
    SUM (CASE WHEN company='foobar' THEN sales ELSE 0 end) as sales_foobar,
    SUM(sales) as sales_total, 
    country, 
    year, 
    product 
        FROM sales_table
            GROUP BY country, year, product 
                HAVING SUM (CASE WHEN company='foobar' THEN sales ELSE 0 end) > 0