我如何通过url在django中传递变量?

问题描述 投票:7回答:2

我正在尝试传递一些变量,但遇到一些麻烦,特别是3个问题。如何编码url字符串以考虑字符串中的特殊字符?给定字符串,我应该使用什么正确的正则表达式?以及如何解码已编码的网址?

视图

author = 'foo'
video = 'bar123-456'
title = 'Santorum: "I'm Not a Visionary"' # in my version, it is referencing another variable so the syntax error doesn't occur. But I left it in here because I want to know how to deal with " and '.
related = 'http://gdata.youtube.com/feeds/api/users/haha/uploads?v=2&max-results=50'

url = urllib.quote('partner/' + author+ '/'+ video+'/'+ title + '/' + related)
#How do I encode this url string above to take into account the special characters in the string?

模板

<a href="/{{url}}" > <img src="img.png" > </a>

urls.py

url(r'^partner/(?P<partner_name>[-\w]+)/(?P<video_id>[-\w]+)/(?P<video_title>[-\w]+)//(?P<related_feed>)/$', 'video_player'),
#do I have to add anything to the regex?

视频播放器功能

def video_player(request, author, video, related):
    #how do I decode the urls that are encoded

编辑

我尝试了一下但没有发现它是否起作用,但是仍然出现错误。

模板:

<a href="{% url 'reserve.views.video_player' author video title   %}" >

url:

url(r'^partner/(?P<author>[-\w]+)/(?P<video>[-\w]+)/(?P<title>[-\w]+)/$', 'video_player'),

我收到此错误:

在/ partner / BuzzFeed /带有参数'('BuzzFeed','fXkqhhIlOtA','NY Yankees:季后赛大事记的6个基本要素')'和关键字参数'{}'的“ video_player”反向显示。

完整urls.py

urlpatterns = patterns('reserve.views',
    url(r'^$', 'index'),
    url(r'^browse/$', 'browse'),
    url(r'^faq/$', 'faq'),
    url(r'^about/$', 'about'),
    url(r'^contactinfo/$', 'contactinfo'),
    url(r'^search/$', 'search'),
    (r'^accounts/', include('registration.backends.default.urls')),
    (r'^accounts/profile/$', 'profile'),
    (r'^accounts/create_profile/$', 'user_profile'),
    (r'^accounts/edit_profile/$', 'edit_profile'),
    url(r'^products/(?P<product_name>[-\w]+)/reviews/$', 'view_reviews'),
    url(r'^products/(?P<product_id>\d+)/reviews/$', 'view_reviews'),
    url(r'^user/(?P<user_id>[-\w]+)/$', 'view_reviews_user'),
    #url(r'^category/(?P<category_name>[-\w]+)/$', 'view_product_category'),
    url(r'^partner/(?P<partner_name>[-\w]+)/$', 'partner_channel'),
    url(r'^partner/(?P<author>[-\w]+)/(?P<video>[-\w]+)/(?P<video_title>[-\w]+)/$', 'video_player'),
    url(r'^partner/(?P<author>[-\w]+)/(?P<video>\w+)/(?P<title>\w+)/$', 'video_player'),
    url(r'^admin/', include(admin.site.urls)),
)
python django templates url view
2个回答
16
投票

将这些变量原样传递到模板,在那里使用url,然后再发送到模板,只需在视图中执行此操作。

View.py

related = urllib.quote(related, safe='')

模板

<a href="{% url 'path.to.video_player' author video related %}" > <img src="img.png" > </a>

Url.py

url(r'^partner/(?P<author>[-\w]+)/(?P<video>\w+)/(?P<related>\w+)/$', 'video_player'),

编辑

如果您想不使用相关参数,或者怀疑视频是否也可以是None,那么只需在您的视图中执行此操作:

def video_player(request, author, video=None, related=None):

现在您可以通过]使用url>

<a href="{% url 'path.to.video_player' author video %}" > <img src="img.png" > </a>

0
投票

在较新版本的python中,您只需键入:示例:

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